<u>Answer:</u> The mass of manganese(III) oxide produced is 113.03 g
<u>Explanation:</u>
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
......(1)
Given mass of zinc = 46.8 g
Molar mass of zinc = 65.38 g/mol
Plugging values in equation 1:
The given chemical equation follows:
By the stoichiometry of the reaction:
If 1 mole of zinc produces 1 mole of manganese(III) oxide
So, 0.716 moles of zinc will produce = of manganese(III) oxide
Molar mass of manganese(III) oxide = 157.87 g/mol
Plugging values in equation 1:
Hence, the mass of manganese(III) oxide produced is 113.03 g
Answer:
0.906 moles of calcium carbonate needed to produced 0.906 moles of carbon dioxide.
Explanation:
Given data:
Moles of carbon dioxide produced = 0.906 mol
Moles of calcium carbonate needed = ?
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Now will compare the moles of carbon dioxide with calcium carbonate:
CO₂ : CaCO₃
1 : 1
0.906 : 0.906
So 0.906 moles of calcium carbonate needed to produced 0.906 moles of carbon dioxide.
Answer:
0.16 moles of Ar
Explanation:
One mole is equal to 6.022×10^23 atoms
9.63 x 10^22 atoms * 1 mol/6.022×10^23 atoms = 0.15991364995 moles
The scientific method -APEX- with a good idea of the expected experimental results <span>to analyze their new results to match up with to old ones.
Hope this helps! </span>