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3 years ago

HELPPP LOOK AT PICTURE

Chemistry

1 answer:

lina2011 [118]3 years ago

5 0

Answer:

it is a square

Explanation:

I hope it will helps you

sorry it's not a true answer

because I want points

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Write a balanced chemical equation for the reaction that occurs when Mg(s) reacts with Cl2(g).

Julli [10]

Explanation:

When magnesium reacts with chlorine then it forms magnesium chloride.

Equation -

Mg + Cl₂ → MgCl₂

This is the example of Combination reaction.

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3 years ago

Predictable moderate winds between 5 & 25 degrees North or South latitude are called?

Grace [21]

Answer:

احبـــــــــــــــــــك

لول ملل اقولج انا اسفه

6 0

3 years ago

Calculate the pH of a solution that contains 2.7 M HF and 2.7 M HOC6H5. Also, calculate the concentration of OC6H5- in this solu

borishaifa [10]

Answer:

$\large \boxed{\mathbf{1.36; 3.6 \times 10^{\mathbf{-9}}}\textbf{mol/L}}$

Explanation:

The HF is about five million times as strong as phenol, so it will be by far the major contributor of hydronium ions. We can ignore the contribution from the phenol.

1 .Calculate the hydronium ion concentration

We can use an ICE table to organize the calculations.

HF + H₂O ⇌ H₃O⁺ + F⁻

I/mol·L⁻¹: 2.7 0 0

C/mol·L⁻¹: -x +x +x

E/mol·L⁻¹: 2.7 - x x x

$K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}] \text{F}^{-}]} {\text{[HF]}} = 7.2 \times 10^{-4}\\\\\dfrac{x^{2}}{2.7 - x} = 7.2 \times 10^{-4}\\\\\text{Check for negligibility of }x\\\\\dfrac{2.7}{7.2 \times 10^{-4}} = 4000 > 400\\\\\therefore x \ll 2.7\\\dfrac{x^{2}}{2.7} = 7.2 \times 10^{-4}\\\\x^{2} = 2.7 \times 7.2 \times 10^{-4} = 1.94 \times 10^{-3}\\x = 0.0441\\\text{[H$_{3}$O$^{+}$]}= \text{x mol$\cdot$L$^{-1}$} = \text{0.0441 mol$\cdot$L$^{-1}$}$

2. Calculate the pH

$\text{pH} = -\log{\rm[H_{3}O^{+}]} = -\log{0.0441} = \large \boxed{\mathbf{1.36}}$

3. Calculate [C₆H₅O⁻]

C₆H₅OH + H₂O ⇌ C₆H₅O⁻ + H₃O⁺

2.7 x 0.0441

$K_{\text{a}} = \dfrac{0.0441x} {2.7} = 1.6 \times 10^{-10}\\\\0.0441x = 1.6 \times 10^{-10}\\x = \dfrac{1.6 \times 10^{-10}}{0.0441} = \mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}\\\text{The concentration of phenoxide ion is $\large \boxed{\mathbf{3.6 \times 10^{\mathbf{-9}}}\textbf{ mol/L}}$}$

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3 years ago

The pressure of a gas is 750 torr when its volume is 400. ml. Calculate the

ololo11 [35]

Answer:

a. 0.66 atm

Explanation:

Pi = 750 torr = 0.99 atm. Pf = ?

Vi = 400 ml Vf = 600ml

Using PiVi = PfVf

Then 400ml × 0.99atm = Pfatm × 600ml

Solving for Pf, we have,

Pf = (400ml × 0.99atm)/600ml

Pf = 0.66atm

7 0

2 years ago

I need help with this answer

frez [133]

A
not every expirement has control

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3 years ago