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3 years ago

A car’s original price was $26,500. Mr. Thomas paid $18,815. What percent discount did Mr. Thomas receive on the car?

Mathematics

2 answers:

Grace [21]3 years ago

6 0

B. He received 29% discount on the car.

bagirrra123 [75]3 years ago

6 0

7.1%. Do 18,185/26500 to find the percentage difference in decimal form. Hope I helped

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Solve for x I need help again :/

vovangra [49]

Answer:

x = 6

Step-by-step explanation:

opposite sides of both angles are congruent/equal or have same measure.

Therefore:-

6x+2=38

6x=38-2

6x=36

x = 6

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2 years ago

Tia used a photocopier to dilate the design for a monorail track system. The figure shows the design and its photocopy:

Nastasia [14]

Answer:

I think its 28.

Step-by-step explanation: Dont take my word for this tho

the ratio is 1:2 and that would mean that whatever length DA, HE is 2 times.

The length of BC is 14 so 14 x 2 is 28.

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2 years ago

Someone please help me

Firdavs [7]

Answer:

x = -3/2

Step-by-step explanation:

The removable discontinuity is at the value of x where a denominator factor cancels a numerator factor, and those factors are zero.

$p(x)=\dfrac{2x+3}{4x^2-9}=\dfrac{2x+3}{(2x+3)(2x-3)}=\dfrac{2x+3}{2x+3}\cdot\dfrac{1}{2x-3}\\\\p(x)=\dfrac{1}{2x-3}\qquad x\ne-3/2$

That cancellation occurs where 2x+3 = 0, at x=-3/2.

The function p(x) has a removable discontinuity when x = -3/2.

4 0

2 years ago

Need help please!! Will give points

Nataly [62]

Answer:

1. $\bar X=5.10$

2. $\sigma=0.47$

3. $\sigma^2=0.22$

Step-by-step explanation:

QUESTION 1

The given data set for the expenditure is

$4.85,5.10,5.50,4.75,4.50,5.00,6.00$

The formula for calculating the mean is given by,

$\bar X=\frac{\sum x}{n}$

We need to add all the expenditure and divide by the total number of days.

$\bar X=\frac{4.85+5.10+5.50+4.75+4.50+5.00+6.00}{7}$

This gives us,

$\bar X=\frac{35.7}{7}$

$\Rightarrow \bar X=5.10$ to the nearest hundredth.

QUESTION 2

The standard deviation of the data set is given by the formula;

$\sigma =\sqrt{\frac{\sum(x-\bar X)^2}{n} }$

This implies that,

$\sigma =\sqrt{\frac{(4.85-5.10)^2+(5.10-5.10)^2+(5.50-5.10)^2+(4.75-5.10)^2+(4.50-5.10)^2+(5.00-5.10)^2+(6.00-5.10)^2}{7} }$

This will give us,

$\sigma =\sqrt{\frac{(-0.25)^2+(0.00)^2+(0.40)^2+(-0.35)^2+(-0.60)^2+(-0.10)^2+(0.90)^2}{7} }$

$\sigma =\sqrt{\frac{0.0625+0+0.16+0.1225+0.36+0.01+0.81}{7} }$

$\sigma =\sqrt{\frac{61}{280} }$

$\sigma =0.466775$

to the nearest hundredth,

$\sigma =0.47$ .

QUESTION 3

The variance is the square of the standard deviation.

$\sigma^2 =(0.46675)^2$

$\sigma^2 =0.217857$

To the nearest hundred gives,

$\sigma^2 =0.22$

3 0

3 years ago

QUESTION OF THE DAY: There are 5 blue M&Ms, 6 red M&Ms, 5 yellow M&Ms, 8 green M&Ms, 4 orange M&Ms, and 7 br

Nadya [2.5K]

Answer:

15/35

Step-by-step explanation:

7 0

3 years ago