Answer:
its blurry for me sorry
Step-by-step explanation:
Answer:
Im not sure but i think its the 3rd but Im sure its the 5th one
Step-by-step explanation:
sorry Im not good a math
The probability of getting 3 or more who were involved in a car accident last year is 0.126.
Given 9% of the drivers were involved in a car accident last year.
We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.
We have to use binomial theorem which is as under:
n
where p is the probability an r is the number of trials.
Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]
=1-{
}
=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}
=1-{0.2670+0.3654+0.2358}
=1-0.8682
=0.1318
Among the options given the nearest is 0.126.
Hence the probability that 3 or more are involved in the accident is 0.126.
Learn more about probability at brainly.com/question/24756209
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Answer:
The weight of the block that Katie has is 16 1/3 pounds
Step-by-step explanation:
<u>Katie has: 4 full cement blocks and 4/6 (or 2/3 ) of the normal size of a cement block</u>
For one full block, it weighs 3 2/4 ( or 1/2) pounds, if you want to find the answer of the question, you need to multiply the weight with the cement blocks that Katie have.
<u>First do the four full cement blocks:</u>
4 * 3 2/4 = ?
4 * 14/4 = ?
Cancel the 4 that is being multiplied and the 4 that is being divided by 14.
= 14.
<u>Now do the 4/6 (or 2/3) cement block:</u>
2/3 * 3 2/4 = ?
2/3 * 14/4 = ?
Multiply the fractions together:
= 28/12
= 2 1/3
<u>Finally, you add up the full blocks and the 2/3 cement block to get your answer:</u>
2 1/3 + 14 = 16 1/3
The weight of the block that Katie has is 16 1/3 pounds