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fenix001 [56]
3 years ago
9

Given that tan? Tan^2 0=3/8 what is the value of sec 0?

Mathematics
1 answer:
Ronch [10]3 years ago
7 0

Answer:

1.068.

Step-by-step explanation:

Use the identity

sec^2 O = 1 + tan^2 O

=  1 + (3/8)^2

= 1  9/64

= 73/64

so sec O =  √73/8

= 1 .068.

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22. The area of a triangle can be represented by the expression 14x^5 + 63x^2. If the base is 7x^2, write
kkurt [141]

Answer:

h = 4x ^ 3 + 18

Step-by-step explanation:

The first thing you should know for this case is that the area of a triangle is given by:

A = (1/2) * (b) * (h)

Where,

b: base.

h: height.

Clearing the height we have:

h = ((2) * (A)) / (b)

Substituting the values

h = ((2) * (14x ^ 5 + 63x ^ 2)) / (7x ^ 2)

Simplifying the expression:

h = ((2) * (2x ^ 3 + 9))

h = 4x ^ 3 + 18

answer

an expression to represent its height is

h = 4x ^ 3 + 18

4 0
3 years ago
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666

Second step. <u>Calculate the standard deviation</u>

\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}

\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}

\sigma=\sqrt{17.815}=4.22

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).  

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

\bar X \pm t\frac{\sigma}{\sqrt n}

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0
3 years ago
4. Solve using elimination.<br> 4x -3y = 9<br> 3x +2y = 11
UNO [17]
Answer: (3,1)

Explanation:
8 0
3 years ago
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During strenuous work a human body generates about 2,400 BTUs of body heat per hour. If 7 bodybuilders are in a gym that is 20 f
Vlad [161]
The answer is b) 8.4
3 0
3 years ago
Help I have to turn this in. In a couple hours
Gelneren [198K]

28. Surface Area

This is some sort of house-like model so for every face we see there's a congruent one that's hidden.  We'll just double the area we can see.

Area = 2 × ( [14×9 rectangle] + 2[15×9 rectangle]+[triangle base 14, height 6] )

Let's separate the area into the area of the front and the sides; the front will help us for problem 29.

Front =  [14×9 rectangle] + [triangle base 14, height 6]

          = 14×9 + (1/2)(14)(6) = 14(9 + 3) = 14×12 = 168 sq ft

OneSide =  2[15×9 rectangle] = 30×9 = 270 sq ft

Surface Area = 2(168 + 270) = 876 sq ft

Answer: D) 876 sq ft

29.  Volume of an extruded shape is area of the base, here the front, times the height, here 15 feet.  

Volume = 168 * 15 = 2520 cubic ft

Answer: D) 2520 cubic ft

6 0
3 years ago
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