Given that tan? Tan^2 0=3/8 what is the value of sec 0?
1 answer:
Answer:
1.068.
Step-by-step explanation:
Use the identity
sec^2 O = 1 + tan^2 O
= 1 + (3/8)^2
= 1 9/64
= 73/64
so sec O = √73/8
= 1 .068.
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