Answer:
i hope this will help you :)
Explanation:
number of electrons=36
number of protons=36
number of neutrons=42
mass number=number of protons+number of neutrons
mass number=36+42
mass number=78
so the element will be krypton Kr
as elements are identified on their number of electrons so this atom is krypton
as the actual atomic mass of krypton is 86 here the calculated atomic mass is 78 so krypton has loss 8 electrons but this must require a great amount of energy so the charge on krypton is +8
Answer:
17.4
Explanation:
kasi 15.2
16.2
=17.4 thanks me later pa brainliest din
The answer is: " 56 g CaCl₂ " .
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Explanation:
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2.0 M CaCl₂ = 2.0 mol CaCl₂ / L ;
Since: "M" = "Molarity" (measurement of concentration);
= moles of solute per L {"Liter"} of solution.
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Note the exact conversion: 1000 mL = 1 L .
Given: 250 mL ;
250 mL = ? L ? ;
250 mL * (1 L / 1000 L) = (250/1000) L = 0.25 L .
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(2.0 mol CaCl₂ / L ) * (0.25L) = (2.0) * (0.25) mol = 0.50 mol CaCl₂ ;
We have: 0.50 mol CaCl₂ ; Convert to "g" (grams):
→ 0.50 mol CaCl₂ .
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1 mol CaCl₂ = ? g ?
From the Periodic Table of Elements:
1 mol Ca = 40.08 g
1 mol Cl = <span>35.45 g .
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There are 2 atoms of Cl in " CaCl₂ " ;
→ Note the subscript, "2", in the " Cl₂ " ;
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So, to calculate the molar mass of "CaCl₂" :
40.08 g + 2(35.45 g) =
40.08 g + 70.90 g = 110.98 g ; round to 4 significant figures;
→ round to 111 g/mol .
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So:
→ 0.50 mol CaCl₂ = ? g CaCl₂ ? ;
→ 0.50 mol CaCl₂ * (111 g CaCl₂ / mol CaCl₂) ;
= (0.50) * (111 g) CaCl₂ ;
= 55.5 g CaCl₂ ;
→ round to 2 significant figures;
→ 56 g CaCl₂ .
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The answer is: " 56 g CaCl₂ " .
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Answer:
A pure substance has a sharp melting point (melts at one temperature) and a sharp boiling point (boils at one temperature). A mixture melts over a range of temperatures and boils over a range of temperatures. Homogeneous mixtures are called solutions.
Answer:
cu+2 ------ oxidation whereas Cu ------ reduction.
Explanation:
In the reaction, cu+2 is the place where oxidation occurs because this cupric ion losses electrons which causes +2 charge on it. we know that oxidation is the loss of electrons and reduction is the gaining of electrons so the Cu is the place or atom at which reduction occurs. Electrochemical cells have two electrodes, which is anode and the cathode. The anode is the electrode where oxidation occurs whereas the cathode is the electrode where reduction takes place.
