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Maru [420]
3 years ago
11

How many moles of sodium cyanide (NaCN) would be needed to produce 4.2 moles of sodium sulfate (Na2SO4)? H2SO4 + 2NaCN → 2HCN +

Na2SO4
Chemistry
2 answers:
Alexus [3.1K]3 years ago
6 0

Answer: 8.4 mol NaCN

Explanation: I just took the quiz and it was correct:)

leonid [27]3 years ago
4 0
The purpose of a chemical equation is to relate the amounts of reactants to the amounts of products based on the rate each is consumed. In this problem, one mole of sulfuric acid is consumed along with two moles of sodium cyanide to produce two moles of hydrocyanic acid and one mole of sodium sulfate. The relationship between sodium cyanide and sodium sulfate is 2:1, meaning that two moles of NaCN is required to produce one mole of sodium sulfate.

To produce 4.2 moles of sodium sulfate, two times this amount of NaCN is required. This means that you would need 8.4 moles of sodium cyanide.

Hope this helps!
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A solution of potassium nitrate is made when potassium nitrate dissolves in water.
kondor19780726 [428]

Answer:

Boil the water and stir in potassium nitrate. If it doesn't all dissolve, you can cook it on the stove or microwave it until the water boils again. Remove the solution from heat, but let it cool slowly for the best crystal formation.

3 0
1 year ago
Gasoline has a density of 0.749 g/mL. How many pounds does 19.2 gallons of gasoline weigh? Use significant figures. Do not enter
Yanka [14]
In this question, you are given the gasoline density (0.749g/ml) and volume of the gasoline (19.2 gallons). You are asked the mass of the gasoline in pounds. Then you need to change the grams into pounds and the ml into gallons. The calculation would be:

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7 0
3 years ago
What factors influence the gravitational forces between objects?
lisabon 2012 [21]

Explanation:

F = k.m1.m2/r²

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5 0
3 years ago
A gas has a volume of 3.25 liters at 54 C and 231 kPa of pressure. At what temperature will the same gas take up 4.35 liters of
Firdavs [7]

Answer: 318 K

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 231 kPa

P_2 = final pressure of gas = 168 kPa

V_1 = initial volume of gas = 3.25 L

V_2 = final volume of gas = 4.35 L

T_1 = initial temperature of gas = 54^oC=273+54=327K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{231\times 3.25}{327}=\frac{168\times 4.35}{T_2}

T_2=318K

At 318 K of temperature will the same gas take up 4.35 liters of space and have a pressure of 168 kPa

4 0
3 years ago
C) A football feels hard on a hot day but feels softer in the evening​
Mariana [72]

Answer: ^_^

Explanation:

its because during day time the ball becomes heated up and the air inside it try to come out as the heat air always try to go up swelling up the ball,

so in the evening when the air cools down the ball too cools down and air inside it also cools down making the ball feel soft,

Therefore, a football feels hard on a hot day but feels softer in the evening​

Hope it helped u,

pls mark as the brainliest

^_^

5 0
3 years ago
Read 2 more answers
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