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3 years ago

If a wave has a wave height of 5 meters, in what depth of water would it begin to break?

Chemistry

1 answer:

Marysya12 [62]3 years ago

4 0

Answer:

6.5 meters

Explanation:

Background Knowledge:

The most familiar example of breaking wave is the breaking of water surface waves on a coastline.

Explanation:

The process of Wave breaking in most of the cases occurs when the amplitude reaches the point that the crest of the wave actually overturns

Factors by which waves are produced:

Different type of waves are produced and varied according to different type of factors. These factors are

Wind direction

Type of swell

Sea floor features

Slope of sea bed

Direct answer of the question:

In general rule, Waves start to break on reaching a water depth of 1.3 times the wave height.

In this question wave height is 5 meters so wave breaks on

5 × 1.3 = 6.5 meters

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Answer:

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2 years ago

Read 2 more answers

Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely wit

vfiekz [6]

Answer:

4 moles, 160 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $H_2SO_4$ :-

Mass of $H_2SO_4$ = 196 g

Molar mass of $H_2SO_4$ = 98 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{196\ g}{98\ g/mol}$

$Moles\ of\ Sulfuric\ acid= 2\ mol$

According to the given reaction:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

<u>Mass = Moles*molar mass = $4\times 40\ g$ = 160 g</u>

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2 years ago

Noble Gases (18): (Name all noble gases)

Paul [167]

Answer :

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3 years ago

What gives the gem amethyst its purplish color?

Alina [70]

iron Presence of trace elements, irradiation and iron impurities give the gem amethyst its purplish color!

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2 years ago

Cl2 + 2OH− → Cl− + ClO− + H2O

Nataly_w [17]

Cl2(g) -------> Cl-(aq) + ClO-(aq)

2e- + Cl2(g) -------> 2Cl-(aq) [reduction]

4OH-(aq) + Cl2(g) -----------> 2ClO-(aq) + 2H2O(l) + 2e- [oxidation]
______________________________________...
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3 years ago