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ANEK [815]
4 years ago
5

The atomic mass of iron is 55.85, and oxygen is 16.0. What is the mass of 6.02 × 1023 molecules of Fe2O3?

Chemistry
2 answers:
Sauron [17]4 years ago
5 0
<span>As there are two atoms of Fe and three atoms of O in the molecule of Fe2O3:
So,
Multiplying no of atoms with the molar mass ,
55.85 *2 + 3* 16 = 159.7g
So according to above explanation,
</span><span>C. 159.7 g ,is the correct answer.</span>
TiliK225 [7]4 years ago
4 0
Molar mass Fe2O3 = 55.85 x 2 + 16.0 x 3 => 159.7 g/mol

159.7 g ---------------- 6.02x10²³ molecules
( mass ) ------------- 6.02 x 10²³ molecules

mass = (6.02x10²³ ) x 159.7 / 6.02x10²³

mass = 9.61x10²⁵ / 6.02x10²³

 = 159.7 g

answer C

hope this helps!
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Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

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c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



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