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bekas [8.4K]
3 years ago
13

What does Mg stand for in chemistry

Chemistry
2 answers:
SCORPION-xisa [38]3 years ago
8 0
- - In relation towards chemistry, Mg is equal to and standing for <span>magnesium(mg).



</span>
makkiz [27]3 years ago
3 0
Mg is an element that stands for Magnesium.

Mg is the chemical symbol for Magnesium. 
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Which mixture is classified as a solution?
svlad2 [7]
Salt water is considered to be a solution
5 0
3 years ago
Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, how many
prisoha [69]

337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles


Read more on moles here:

brainly.com/question/15356425

Hope it helps

7 0
2 years ago
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6 0
3 years ago
Read 2 more answers
The standard internal energy change for a reaction can be symbolized as Δ U ∘ rxn or Δ E ∘ rxn . For each reaction equation, cal
rosijanka [135]

Answer : The internal energy change is, -506.3 kJ/mol

Explanation :

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -511.3kJ/mol=-511300.0J/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles

Change in moles = Number of moles of product side - Number of moles of reactant side

According to the reaction:

Change in moles = 0 - 2 = -2 mole

That means, value of \Delta n_gRT = 0

R = gas constant = 8.314 J/mol.K

T = temperature = 25^oC=273+25=298K

Now put all the given values in the above formula, we get

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-511300.0J/mol)-[-2mol\times 8.314J/mol.K\times 298K

\Delta U=-511300.0J/mol+4955.144J/mol

\Delta U=-506344.856J/mol=-506.3kJ/mol

Therefore, the internal energy change is -506.3 kJ/mol

6 0
3 years ago
What is the pressure, in atmospheres, of a 0.108-mol sample of helium gas at a temperature of 20.0°C if its volume is 0.505 L?
SpyIntel [72]

Answer:

P = 5.14ATM

Explanation:

Number of moles = 0.108moles

Temperature (T) = 20°C = 20 + 273.15 = 293.15K

Volume V = 0.505L.

Pressure (P) = ?

R = 0.082J/mol.K

From ideal gas equation,

PV = nRT

P = nRT / V

P = (0.108 * 0.082 * 293.15) / 0.505

P = 2.596 / 0.505

P = 5.14ATM

The pressure of the gas is 5.14ATM

5 0
3 years ago
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