I need to know the answer to that

PLS FAST WILL GIVE BRAINLIEST!! Examine the statement.

tatiyna

Answer:

I agree

Explanation:

For scientists working in classified areas, collaboration with university programs and researchers provides opportunities to expand and strengthen their science through the conduct of peer-reviewed, open literature research.

4 0

3 years ago

Please help me solve this!

yulyashka [42]

Answer : The image is attached below.

Explanation :

For $O_3$ :

Molar mass, M = 48 g/mol

Mass, m = 24 g

Moles, n = $\frac{m}{M}=\frac{24g}{48g/mol}=0.5mol$

Number of particles, N = $n\times 6.022\times 10^{23}=0.5\times 6.022\times 10^{23}=3.0\times 10^{23}$

For $NH_3$ :

Molar mass, M = 17 g/mol

Mass, m = 170 g

Moles, n = $\frac{m}{M}=\frac{170g}{17g/mol}=10mol$

Number of particles, N = $n\times 6.022\times 10^{23}=10\times 6.022\times 10^{23}=6.0\times 10^{24}$

For $F_2$ :

Molar mass, M = 38 g/mol

Mass, m = 38 g

Moles, n = $\frac{m}{M}=\frac{38g}{38g/mol}=1mol$

Number of particles, N = $n\times 6.022\times 10^{23}=1\times 6.022\times 10^{23}=6.0\times 10^{23}$

For $CO_2$ :

Molar mass, M = 44 g/mol

Moles, n = 0.10 mol

Mass, m = $n\times M=0.10mol\times 44g/mol=4.4g$

Number of particles, N = $n\times 6.022\times 10^{23}=0.10\times 6.022\times 10^{23}=6.0\times 10^{22}$

For $NO_2$ :

Molar mass, M = 46 g/mol

Moles, n = 0.20 mol

Mass, m = $n\times M=0.20mol\times 46g/mol=9.2g$

Number of particles, N = $n\times 6.022\times 10^{23}=0.20\times 6.022\times 10^{23}=1.2\times 10^{23}$

For $Ne$ :

Molar mass, M = 20 g/mol

Number of particles = $1.5\times 10^{23}$

Moles, n = $\frac{N}{6.022\times 10^{23}}=\frac{1.5\times 10^{23}}{6.022\times 10^{23}}=0.25mol$

Mass, m = $n\times M=0.25mol\times 20g/mol=5g$

For $N_2O$ :

Molar mass, M = 44 g/mol

Number of particles = $1.2\times 10^{24}$

Moles, n = $\frac{N}{6.022\times 10^{23}}=\frac{1.2\times 10^{24}}{6.022\times 10^{23}}=1.9mol$

Mass, m = $n\times M=1.9mol\times 44g/mol=83.6g$

For unknown substance:

Number of particles = $3.0\times 10^{23}$

Mass, m = 8.5 g

Moles, n = $\frac{N}{6.022\times 10^{23}}=\frac{3.0\times 10^{23}}{6.022\times 10^{23}}=0.50mol$

Molar mass, M = $\frac{m}{n}=\frac{8.5g}{0.50mol}=17g/mol$

The substance is $NH_3$ .

3 0

2 years ago

The original gas volume in a balloon is 50.mL when the pressure is 1.00 atm. Predict the new gas volume when the pressure is 3 t

damaskus [11]

According to Boyle's law, Volume is indirectly proportional to the pressure.

So, P1V1 = P2V2

Substitute the known values,
1 * 50 = 3 * V2

V2 = 50/3 = 16.67 mL

In short, Your Answer would be: 16.67 mL

Hope this helps!

5 0

3 years ago

Convert 7.89 x 10^8 molecules of water to liters.

NNADVOKAT [17]

Answer:

2.94 x 10⁻¹⁴L

Explanation:

To solve this problem, we have to assume that the condition of this water is at standard temperature and pressure, STP.

At STP;

1 mole of gas have a volume of 22.4L

So, let us find the number of moles of this water first;

6.02 x 10²³ molecules can be found in 1 mole of a substance

7.89 x 10⁸ molecules will contain $\frac{7.89 x 10^{8} }{6.02 x 10^{23} }$ = 1.31 x 10⁻¹⁵mole of water

So;

Volume of water = 22.4 x 1.31 x 10⁻¹⁵ = 2.94 x 10⁻¹⁴L

5 0

3 years ago

How many moles of MgCl2 where needed to make a 650.0 mL solution a concentration of 0.962 M?

Murljashka [212]

Answer:

0.625 moles MgCl₂

Explanation:

Since you were given a molarity value and volume, you should use the molarity equation to find moles. The equation looks like this:

Molarity (M) = moles / volume (L)

To find moles, you need to (1) convert mL to L (by dividing by 1,000) and then (2) plug the numbers into the formula and simplify to find moles. The final answer should have 3 sig figs as the lowest amount of sig figs in a given value is 3.

650.0 mL / 1,000 = 0.6500 L

Molarity = moles / volume

0.962 M = moles / 0.6500 L

(0.962 M) x (0.6500 L) = moles

0.625 = moles

5 0

2 years ago