Answer:
The answer is "
"
Step-by-step explanation:
Please find the graph file in the attachment.
The area of its tree house's outsides of the square walls and triangular ceilings is equivalent to four squares with four triangles,
![\to A=4[(6)^2+\frac{1}{2} (6)(6)]\\\\](https://tex.z-dn.net/?f=%5Cto%20A%3D4%5B%286%29%5E2%2B%5Cfrac%7B1%7D%7B2%7D%20%286%29%286%29%5D%5C%5C%5C%5C)
![=4[36+\frac{1}{2} (36)]\\\\=4[36+18]\\\\=4[ 54]\\\\=216\ ft^2](https://tex.z-dn.net/?f=%3D4%5B36%2B%5Cfrac%7B1%7D%7B2%7D%20%2836%29%5D%5C%5C%5C%5C%3D4%5B36%2B18%5D%5C%5C%5C%5C%3D4%5B%2054%5D%5C%5C%5C%5C%3D216%5C%20ft%5E2)
#1. 1000
#2. 1/45 (decimal is .02 with the line above the two
#3. 32/9
#4. 1/20 (decimal form .05
#5. 4
#6. 47/4 (decimal is 11.75)
#7. 1/4 (decimal 0.25
#8. 1/2 decimal is 0.5
#9. 45
#10. 12
I really hope this help
According to the model, the year will the population exceed 470 million is 2060
What is the first step to take?
The first step in this case is to use the model to compute the population figure in each year as shown below:
N = 3.21t + 277.3
Year 2020:
t=20
N = 3.21(20) + 277.3
N=341.50
Year 2025:
t=25
N = 3.21(25) + 277.3
N= 357.55
Year 2030:
t=30
N = 3.21(30) + 277.3
N=373.60
Year 2035:
t=35
N = 3.21(35) + 277.3
N= 389.65
Year 2060:
t=60
N = 3.21(60)+ 277.3
N= 469.90
Year 2065:
t=65
N = 3.21(65)+ 277.3
N= 485.95
Since all the years given do not give the correct year, let us equate the target population figure to the model and solve for t
470= 3.21t + 277.3
470-277.3=3.21t
192.70=3.21t
t=192.70/3.21
t=60.03(approximately 2060)
Find out more about population model on:brainly.com/question/25896797
#SPJ1
Answer:
1/216
1/8 *1/3³ ( cross multiply ) = 1/216
Did you only need the answer for the one on the top right?? Or all of them because If you need all of them I can do that too I am just assuming you just needed that one because it was selected.
