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dimulka [17.4K]
3 years ago
12

Need help on ratio table

Mathematics
1 answer:
guajiro [1.7K]3 years ago
5 0

80.8, 40.4, 20.2, 10.1 (the numbers are going in half.)

1024, 512, 256, 128. (also going in half.)

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Step-by-step explanation:

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What is 15/27 in a decimal?
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0.55555

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Multiply or divide to find two equivalent fractions of 1/2
patriot [66]

Answer:

3/6 and 5/10

Explanation:

Given the fraction 1/2:

(a)Multiply the numerator and denominator by 3

\frac{1}{2}\times\frac{3}{3}=\frac{3}{6}

An equivalent fraction is 3/6.

(b)Multiply the numerator and denominator by 5:

\frac{1}{2}\times\frac{5}{5}=\frac{5}{10}

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1 year ago
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Please answer this question now
Alex787 [66]

Answer:

541.7 (m2)

Step-by-step explanation:

Applying the sine theorem:

WV/sin(X) = XV/sin(W)

=> WV = XV*sin(X)/sin(W) = 37*sin(50)/sin(63) = 31.81

Angle V = 180 - X - W = 180 - 50 - 63 = 67

Denote WH is a height of the triangle VWX, H lies on XV

=> WH = WV*sin(V) = 31.81*sin(67) =  29.28

=> Area of triangle VWX is calculated by:

S = side*height/2 = XV*WH/2 = 37*29.28/2 = 541.7 (m2)

8 0
3 years ago
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

7 0
3 years ago
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