Altitude is height above sea level. The density of air decreases with height. There are two reasons, at higher altitudes there is less air pushing down from above,and gravity is weaker farther from earths center.
Answer:
Percent yield of PI3 = 95.4%
Explanation:
This is the reaction:
2P (s) + 3I2 (g) > 2PI3 (g)
Let's determine the moles of iodine that has reacted.
58.6 g / 253.8 g/mol = 0.231 mol
Ratio is 3:2. Let's make a rule of three to state the moles produced at 100 % yield reaction.
3 moles of I2 react to make 2 moles of PI3
0.231 moles of I2 would make (0.231 .2) / 3 = 0.154 moles of PI3
As we have produced 0.147 moles let's determine the percent yield.
(Yield produced / Theoretical yield) . 100 > (0.147 / 0.154) . 100 = 95.4%
Answer:
The answer is: 18 moles and 1341, 72 grams of KCl
Explanation:
The molarity is defined as the moles of solute ( in this case KCl) in 1 liter of solution:
1L solution-----3 moles of KCl
6L solution-----x= (6L solutionx 3 moles of KCl)/1 L solution= <em>18 moles of KCl</em>
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We calculate the weight of 1 mol of KCl:
Weight 1 mol KCl= Weight K + Weight Cl= 39,09 g + 35, 45 g=74, 54 g/mol
1 mol KCl----- 74, 54 g
18 mol KCl----x= (18 mol KCl x 74, 54 g)/1 mol KCl=<em>1341, 72 g</em>
Answer: I'll leave the answer rounded to three sig figs.
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So, you can say that in a hydrogen atom, an electron located on
n
i
=
2
that absorbs a photon of energy
4.85
⋅
10
−
19
J
can make the jump to
n
f
=
6
.
Explanation:
The question wants you to determine the energy that the incoming photon must have in order to allow the electron that absorbs it to jump from
n
i
=
2
to
n
f
=
6
.
A good starting point here will be to calculate the energy of the photon emitted when the electron falls from
n
i
=
6
to
n
f
=
2
by using the Rydberg equation.
