Which of the following gases will diffuse the fastest at room temperature?
1 answer:
You might be interested in
Explanation:
Let us assume that the given data is as follows.
V = 3.10 L, T = = (19 + 273)K = 292 K
P = 40 torr (1 atm = 760 torr)
So, P =
= 0.053 atm
n = ?
According to the ideal gas equation, PV = nRT.
Putting the given values into the above equation to calculate the value of n as follows.
PV = nRT
0.1643 =
n =
It is known that molar mass of ethanol is 46 g/mol. Hence, calculate its mass as follows.
No. of moles =
mass = g
= 0.315 g
Thus, we can conclude that the mass of liquid ethanol is 0.315 g.
Answer:
36.92 mg of oxygen required for bio-degradation.
Explanation:
Mass of benzene = 30 mg = 0.03 g (1000 mg = 1 g )
Moles benzene =
According to reaction 5 moles of benzene reacts with 15 moles of oxygen gas.
Then 0.0003846 mol of benzene will react with:
of oxygen gas
Mass of 0.0011538 moles of oxygen gas:
0.0011538 mol × 32 g/mol = 0.03692 g = 36.92 mg
36.92 mg of oxygen required for bio-degradation.