
<h2>
Explanation:</h2>
For a better understanding of the problem I've built up two triangles from the given triangular shape. So these two triangles are similar. Therefore, we can solve this problem by using ratios and corresponding sides in this way:

But our goal is to find y. Let's call w the height of the small triangle, then:

Applying the concept of ratios again:

<h2>Learn more:</h2>
Right triangle: brainly.com/question/10684799
#LearnWithBrainly
Answer:
4.58258
Step-by-step explanation:
Pythagorean Theorem:
a² + b² = c²
Input:
2² + x² = 5²
Remember, c² is always the side opposite of the right angle...
4 + x² = 25
21 = x²
x = 4.58258
If my answer is incorrect, pls correct me!
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-Chetan K
Can you show the whole question
Her monthly allowance is $30! hope this helped
Answer:
If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:
(x,-y)
So we only change the sign of the y-component.
Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.
Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.
The original vertices are:
C = (-3, 7)
D = (0, 7)
E = (0, 10)
F = (-3, 10)
Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:
C' = (-3, -7)
D' = (0, -7)
E' = (0, - 10)
F' = (0, - 10)
Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.