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4 years ago

What is the product? (4y - 3)(2x(2)+ 3y-5)

Mathematics

2 answers:

aleksley [76]4 years ago

5 0

Answer:

2 2

4y(2y +3y - 5) - 3(2y + 3y - 5)

3 2 2

=8y + 12y - 20y - 6y - 9y + 15

3 2

=8y + 6y - 29y + 15

Step-by-step explanation:

sergejj [24]4 years ago

3 0

Answer:

12y² + 16xy -12x -29y + 15

Step-by-step explanation:

(4y - 3)(2x · 2 + (3y - 5))

multiply 2x with 2

(4y - 3)(4x + 3y - 5)

distribute (or foil) 4y - 3 into 4x + 3y -5

16xy + 12y² - 20y - 12x - 9y + 15

combine like terms

16xy + 12y² - 29y - 12x + 15

rearrange to the correct order

12y² + 16xy -12x -29y + 15

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Simplify: 5√3+4√12-2√75

svlad2 [7]

Answer:

8 + $5\sqrt{3}$ $-10\sqrt{7}$

Step-by-step explanation:

i just wrote $5\sqrt{3}$ as a decimal

times 2 with $4\sqrt{1}$ and

times 5 with $-2\sqrt{7}$

i might be wrong but hope this helps

3 0

3 years ago

What is 1 and 1/2% of 400?

aniked [119]

$\bf {{ a}}\%\ of\ b \implies \cfrac{{{ a}}}{100}\cdot b\implies {{ a}}\div 100\cdot b\\\\
-----------------------------\\\\
thus
\\\\

\begin{cases}
{{ 1}}\%\ of\ 400 \implies \cfrac{{{ 1}}}{100}\cdot 400\implies {{1}}\div 100\cdot 400\\
--------------\\
{{ \frac{1}{2}}}\%\ of\ 400 \implies \cfrac{{{ \frac{1}{2}}}}{100}\cdot 400\implies {{\frac{1}{2}}}\div 100\cdot 400
\end{cases}$

you tell us

3 0

3 years ago

Two factors multiply to give you -48 and have a sum of -13. What are the factors? *

Kobotan [32]

Answer:

The corrrect answer is -16 and +3

3 0

3 years ago

Read 2 more answers

PLEASE HELP. I WILL VERY MUCH APPRECIATE IT!!!

alexgriva [62]

Answer: