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daser333 [38]
3 years ago
7

Which is the graph of g(x)

Mathematics
1 answer:
Elena L [17]3 years ago
3 0

Answer

there is no graph sooooo idk how to help you


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Brenton’s weekly pay, P(h) , in dollars, is a function of the number of hours he works, h. He gets paid $20 per hour for the fir
iris [78.8K]

Answer:

{h| 0 ≤ h ≤ 60}

Step-by-step explanation:

Next time, please separate the possible answer choices with commas or semi-colons, or put them on separate lines.

The second set says it all:   {h| 0 ≤ h ≤ 60}.  This guy cannot work more than 60 hours per week, and h cannot be negative.

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3 years ago
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it is claimed that proportion in favor of proportion A is greater than 60%. A sample of size 100 found 69 in favor. what is the
GenaCL600 [577]

Answer:

The alternative hypothesis is H_1: p > 0.6.

The critical value is Z_c = 1.645

Step-by-step explanation:

It is claimed that proportion in favor of proportion A is greater than 60%.

This means that at the null hypothesis, we test if the proportion is of at most 60%, that is:

H_0: p \leq 0.6

At the alternative hypothesis, we test if the proportion is more than 60%, that is:

H_1: p > 0.6

What is (are) the critical value?

The critical value is the value of Z with a p-value 1 subtracted by the standard significance level of 0.05, since we are testing if the mean is more than a value, so, looking at the z-table, Z_c = 1.645

7 0
3 years ago
Solve the equation for 3y-4=6-2y
Blababa [14]

the answer for 3y-4=6-2y is y=2

7 0
3 years ago
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The company produced 150 monitors last week. After some of them were sold there were 48 monitors were left. What was the percent
ivann1987 [24]

Answer:  68%

Step-by-step explanation:

150-48=102/150=.68 x 100=68

4 0
4 years ago
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A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three diff
igor_vitrenko [27]

Answer:

(a) 31101

(b) $5.65

(c) $113.38

Step-by-step explanation:

The complete question is:

A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three different prizes: an automobile valued at $20,000, a $125 gas card, or a $5 shopping card. To claim his or her prize, a prospective print on the back of the flier listed the probabilities of winning. The chance of winning the car was 1 out of 31,101, the chance of winning the gas card was 1 out of 31,101, and the chance of winning the shopping card was 31, 099 out of 31,101.

Solution:

The information provided is as follows:

P(\text{Car})=\frac{1}{31101}\\\\P(\text{Gas Card})=\frac{1}{31101}\\\\P(\text{Shopping Card})=\frac{31099}{31101}

(a)

The number of fliers the automobile dealership sent​ out is, <em>n</em> = 31,101.

This is because the probability of winning any of the three prize is out of 31,101.

(b)

Compute the expected value of the prize won by a prospective customer receiving a​ flier as follows:

E(X)=\sum x\times P(X=x)

         =[20000\times \frac{1}{31101}]+[125\times \frac{1}{31101}]+[5\times \frac{31099}{31101}]\\\\=0.6431+0.0040+4.9997\\\\=5.6468\\\\\approx 5.65

Thus, the expected value of the prize won by a prospective customer receiving a​ flier is $5.65.

(c)

Compute the standard deviation of the prize won by a prospective customer receiving a​ flier as follows:

SD(X)=\sqrt{V(X)}=\sqrt{E(X^{2}-(E(X))^{2}}

           =\sqrt{[(20000)^{2}\times \frac{1}{31101}+(125)^{2}\times \frac{1}{31101}+(5)^{2}\times \frac{31099}{31101}]-(5.65)^{2}}\\\\=\sqrt{12854.9011}\\\\=113.37947\\\\\approx 113.38

Thus, the standard deviation of the prize won by a prospective customer receiving a​ flier is $113.38.

8 0
3 years ago
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