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3 years ago

15

C8H10N4O2 is the chemical formula for caffeine. List the 3 remaining elements in caffeine and how many atoms of that element are

present in a molecule of caffeine.

1 answer:

velikii [3]3 years ago

7 0

No idea , sorry. maybe it is.....actually i dont know, sooo sorry

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A sample of CO2(s) and a sample of CO2(g) differ in their

zysi [14]

Units?
CO2 (s) and CO2 (g)

6 0

3 years ago

An element has 7 protons 7 neutrons and 10 electrons what is the mass number

snow_tiger [21]

Answer:A B

How many electrons are there in Florine with a -1 charge? 10

What is the total number of nucleons in helium? 4

What is the mass number of an element if it contains 19 protons, 19 electrons, and 20 protons? 39

What is the atomic number of an element with 7 protons, 10 electrons, and 7 neutrons? 7

Explanation: Credit to GOOGLE

6 0

4 years ago

Suppose that you wanted to determine the density of a small aystal to confirm that is silicon. From the literature, you know sil

Alina [70]

Answer:

Volume of CHCl3 required, V(CHCl3) = 8.02 mL

Volume of CHBr3 required, V(CHBr3) = 11.98 mL

Explanation:

Note: The complete question is incomplete. The complete question is given below:

Suppose now that you wanted to determine the density of a small yellow crystal to confirm that it is silicon. From the literature, you know that silicon has a density of 2.33 g/cm3. How would you prepare 20.0 mL of the liquid mixture having that density from pure samples of CHCl3 (d = 1.492 g/mL) and CHBr3 (d = 2.890 g/mL)? (Note: 1 mL = 1 cm3.)

V(CHCl3) = mL

V(CHBr3) = mL

Density of required mixture of CHCl3 and CHBr3 equals the density of silicon = 2.33 g/mL

Density of CHCl3 = 1.492 g/mL

Density of CHBr3 = 2.890 g/mL

Let the fraction of CHCl3 required be y

Fraction of CHBr3 required will be 1 - y

Density of mixture = ( fraction of CHCl3 * density of CHCl3) + (fraction of CHBr3 * density of CHBr3)

2.33 = (y * 1.492) + (1 - y) * 2.890

2.33 = 1.492y + 2.890 - 2.890y

-0.56 = -1.398y

y = 0.401

Therefore, volume of CHCl3 required = 0.401 * 20 mL = 8.02 mL

Volume of CHBr3 required = (20 - 8.02) = 11.98 mL

8 0

3 years ago

In a _______ wave the matter in the medium moves back and forth at right angles to the direction

Anni [7]

Transverse.

Longitudinal travels in the same direction as medium.

6 0

2 years ago

An aluminum block has a mass of 82.0 g and a volume of 12.8 cm3. what is the block's density to the nearest g/cm3?

aksik [14]

Density is mass over volume. If you put it into a formula it would look like this:

$D = \frac{m}{v}$

Based on the problem given, you can see that the mass of the aluminum block is 82.0 g and the volume is 12.8 cm3. Just put that into your equation and solve for it:

$D = \frac{m}{V}= \frac{82.0g}{12.8cm^{3} } = 6.4g/ cm^{3}$

The answer is then letter C.

6 0

4 years ago