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kherson [118]
3 years ago
12

Describe what happens to the mass number and the atomic number of a nuclide during alpha decay.

Chemistry
2 answers:
trapecia [35]3 years ago
5 0

Protons are positively charged. When a nucleus emits an alpha particle, these changes happen: the mass number decreases by 4. the atomic number decreases by 2.

Digiron [165]3 years ago
3 0

Answer:

The answer to your question is: The mass number will be 4 units lower.

Explanation:

Alpha particles are Helium atoms, which have a mass number of 4 and atomic number of 2.

When an alpha particle is released, the original atom loses 2 protons and and 2 neutrons an we can see in the example.

                             ²²⁶ ₈₈ Ra  ⇒   ²²² ₈₆ Rn   +   ⁴₂ He

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Voilet or purple

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3 years ago
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A part of an mrna molecule with the following sequence is being read by a ribosome: 5' ccg-acg 3' (mrna). the anticodon loop of
monitta

The first trna's anticodon loop, which will complement this mrna, is 3' GGC 5'.

<h3>What is anticodon ?</h3>

A complementary codon in messenger RNA binds to a triplet of nucleotide bases in transfer RNA that identifies the amino acid delivered during protein synthesis at a ribosome.

A codon is a trio of nucleotides, or triplet, that can be found on mRNA and codes for a certain amino acid when it is translated. A bond is created when an anticodon, which is a three-nucleotide sequence on tRNA, meets with the matching sequence on mRNA.

Each tRNA has a trio of bases known as an anti-codon. to determine the entire anti-codon sequence required to match a certain strand of mRNA. to match the complementary nucleotides in the mRNA sequence.

To learn more about anticodon from the given link:

brainly.com/question/14917337

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3 0
2 years ago
What percent of total energy consumption in the u.s in 2010 came from hydroelectric power? select the closest answer
n200080 [17]

Answer:

12% but u can put 8%

Explanation:

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3 years ago
Calculate the molarity of the final solution of Erythrocin B (MW 879.9 g/mol) if a .5028g sample is dissolved in water diluted t
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Answer:

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First, we will calculate the molarity of the solution 1.

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M = 0.5028 g / 879.9 g/mol × 0.100 L

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We can find the concentration of the final solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 5.714 × 10⁻³ M × 5 mL / 100 mL

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7 0
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