Question

Put the following equation of a line into slope-intercept form, simplifying all

Answer 1

Answer:

$4y = 16-2x\\y = \frac{16}{4} - \frac{2x}{4}\\ y = \frac{-1x}{2}+4\\y = 0.5x+4$

Answer 2

Given parameters:

  Equation of the straight line;

                    2x + 4y = 16

The slope intercept form of the equation is y = mx + c

Where m is the slope of the line

            y and x are the coordinates

             c is the intercept

So, the problem is to write the given equation in form of y = mx + c;

 

         2x + 4y = 16

                 4y = 16 - 2x

  Divide through by 2;

                 $\frac{4y}{2}$   = $\frac{16}{2}$ - $\frac{2x}{2}$

                  2y = 8 - x

                    2y = -x + 8

 Then divide by 2 all through;

                    $\frac{2y}{2}$ = $\frac{-x}{2} + \frac{8}{2}$

                   y = $\frac{-x}{2} + 4$

The equation of the line is y = $\frac{-x}{2} + 4$