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tatyana61 [14]
3 years ago
12

Put the following equation of a line into slope-intercept form, simplifying all

Mathematics
2 answers:
Pepsi [2]3 years ago
7 0

Answer:

4y = 16-2x\\y = \frac{16}{4} - \frac{2x}{4}\\ y = \frac{-1x}{2}+4\\y = 0.5x+4

KIM [24]3 years ago
3 0

Given parameters:

  Equation of the straight line;

                    2x + 4y = 16

The slope intercept form of the equation is y = mx + c

Where m is the slope of the line

            y and x are the coordinates

             c is the intercept

So, the problem is to write the given equation in form of y = mx + c;

 

         2x + 4y = 16

                 4y = 16 - 2x

  Divide through by 2;

                 \frac{4y}{2}   = \frac{16}{2} - \frac{2x}{2}

                  2y = 8 - x

                    2y = -x + 8

 Then divide by 2 all through;

                    \frac{2y}{2} = \frac{-x}{2}  + \frac{8}{2}

                   y = \frac{-x}{2}  + 4

The equation of the line is y = \frac{-x}{2}  + 4

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