Answer:
D.They are equal in magnitude and opposite in direction
Explanation:
- Newton's third law states that the action force is always associated with a reaction force.
- When a body 'A' exerts a force on body 'B', it is called the force of action.
- When the body 'B' in turn resist the force of 'A' is called the reaction force. It is the reactive force acted upon by the body 'B' on 'A'.
- This reaction force is equal in magnitude of the action force.
- If the two bodies remain in the same horizontal line, the 'A' exerts a force in the direction towards 'B' and the body 'B' exerts a reaction force in the direction towards 'A'.
- Hence, the two forces that are exerted by the bodies are equal in magnitude and opposite in direction.
Answer:
Kindly find the graphs attached
Explanation:
For figure 1: There is a steady increase in the position of the object as time increases. This is because despite the negative acceleration (deceleration), the object continues to move and cover more ground as time goes by.
<em>The straight line graph is observed because the acceleration is constant and not varying.</em>
For Figure 2: The graph of velocity vs time will have an inverted nature. This is because since the object is decelerating, it is reducing in its velocity as time goes by (increases). <em>This is also in a straight line since the deceleration is constant.</em>
Answer:
See the answers below
Explanation:
We can solve both problems using vector sum.
a)
Let's assume the forces that help the diver dive as positive downward, and the forces that oppose upward, as negative
![F_{resultant}=100+30-85+900\\F_{resultant}=845[N]](https://tex.z-dn.net/?f=F_%7Bresultant%7D%3D100%2B30-85%2B900%5C%5CF_%7Bresultant%7D%3D845%5BN%5D)
The drag force is horizontal d this way in the horizontal direction we will only have the drag force that produces the water stream.
![F_{drag}=50[N]](https://tex.z-dn.net/?f=F_%7Bdrag%7D%3D50%5BN%5D)
b)
Let's assume the forces that propel the rocket upwards as positive and forces like the weight of the rocket and other elements as negative forces.
![F_{resultant}=960+7080-7700\\F_{resultant}=340 [kN]](https://tex.z-dn.net/?f=F_%7Bresultant%7D%3D960%2B7080-7700%5C%5CF_%7Bresultant%7D%3D340%20%5BkN%5D)
Explanation:
Remember Newton's Second Law.

If the force acting on both bikers is the same, we can look at the relationship between acceleration and mass.
If Biker 1 has a mass of 10kg and Biker 2 has a mass of 20kg, and both are being acted upon by a force of 100 N, let's see what that looks like. 

So, given the same force, an object with GREATER mass will have less acceleration.