2,200 Newtons.
F = ma
v f = v i + at
0mls = 20mls + a(.5s)
-20mls/.5s = -40mls squared
-40mls squared (55kg) = 2,200 Newtons.
Hope this helps!
Answer:
Both technicians are correct.
Explanation:
A working coil in a relay can measure resistance between 50 an 200 ohms.
And the terminals in a Relay are the next, considering the German International Automotive industry standard DIN 72552:
85 Coil
86 Coil
87 NO Normally open
30 Common
So Measuring between terminal 30 and 87 must be an open circuit, and the ohmmeter must show infinite resistance or "OL".
Answer:
0.536 A
Explanation:
From the question,
The combined resistance of the parallel connection is given as
1/Rt = 1/4+1/6+1/10
Rt = 120/15
Rt = 8 ohms.
Since the the combination is connected in series with a 10 ohms resistor,
Rt' = 8+10 = 18 ohms.
Current flowing through the series circuit
I = V/Rt'
V = 12 V, Rt' = 18 ohms
I = 12/18
I = 0.67 A.
Therefore voltage across the combined resistor
V' = 8(0.67)
v' = 5.36 V.
Since the resistors a connected in parallel, the same voltage drop across them.
Therefore, current through the 10 ohms
Ix = 5.36/10
Ix = 0.536 A
C. it’s amplitude. any comments leave them
Hi,
The correct answer is letter B.
The last group contains noble gases, while both along the top and along the bottom the elements on the right are non-metals.