The electromagnetic spectrum is divided into seven different frequency ranges which are from lowest to highest, radio waves, microwaves, infrared, visible light, ultraviolet, X-rays and gamma rays.
The electromagnetic spectrum includes electromagnetic waves with frequencies between one hertz and above 10²⁵ hertz, or wavelengths between thousands of kilometres and a small portion of the size of an atomic nucleus. The electromagnetic waves found within each of these bands are referred to by a different name. Starting at the low frequency(long wavelength), end of the spectrum, these are radio waves, micro waves, infrared, visible light, ultraviolet, x-rays and gamma rays. This frequency range is divided into separate bands.
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Answer:
λ = 548.7 nm
Explanation:
Hi!
First we want to know how much energy we need to remove 1 electron from the surface of the solid:
218.1 kJ/mol => 218 100 J / (6.022 x 10^23) electrons
= 3.621 x 10^-19 J/electron
That is we need 3.621 x 10^-19 J to remove one electron
Now we can calculate the wavelength that a photon must have in order to have this energy:
E = (hc) / λ
λ = (hc) / Ε
where
h = 6,626070150(69) ×10 -34 Js (wikipedia)
c = 3 x10^8 m/s
hc = 1.987 x 10^-25 Jm
Therefore:
λ = ( 1.987 x 10^-25 /3.621 x 10^-19 ) m = 5.487 x 10^-7 m
λ = 548.7 nm
Answer:
Frequency of sound wave = 198.83 hertz (Approx.)
Explanation:
Given:
Velocity of sound wave in air = 340 m/s
Wavelength = 1.71 meter
Find:
Frequency of sound wave
Computation:
Frequency = Velocity / Wavelength
Frequency of sound wave = Velocity of sound wave in air / Wavelength
Frequency of sound wave = 340 / 1.71
Frequency of sound wave = 198.8304
Frequency of sound wave = 198.83 hertz (Approx.)
Capacitance is a measure of charge stored per volt.
<span>F=ma = 3000x2m/sec^2 =6000 newtons. </span>
