i think it’s is a for the first one
Answer:
9
Step-by-step explanation:
first add 3 and 5 =8
then add 1/2 and 1/2 =1
8+1 =9
In this case it is to find the roots of the polynomial.
We have then:
2x ^ 2-5x + 1 = 3
Rewriting:
2x ^ 2-5x-2 = 0
Applying resolver we have
x = (- b +/- root (b ^ 2 - 4ac)) / (2a)
Substituting values:
x = (- (- 5) +/- root ((- 5) ^ 2 - 4 (2) (- 2))) / (2 (2))
x = (- (- 5) +/- root ((25 + 16)) / (2 (2))
x = (5 +/- root (41))) / (4)
x = ((5/4) +/- (root (41)) / 4)
Answer:
x = ((5/4) +/- (root (41)) / 4)
(option 4)
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Formula
A = L * W
Givens
W = W
L = W + 2
Solution
Area = L*W
Area = (W+2)*W = 80 Remove the brackets.
Area = W^2 + 2W = 80 Subtract 80 from both sides.
Area = w^2+2W-80=80-80 Combine
Area = w^2 +2W-80 = 0 Factor.
Area = (w+10)(w - 8) = 0
W + 10 = 0 won't work
W = - 10 which isn't possible
W- 8 = 0
W = 8
L = 8 + 2 = 10
The answer looks like A