SOLUTION is given in attachment below.
Given the mass of R-134a m = 300kg; Volume of the container V = 9 cu. meter; Temperature of R-134a T = 10 degrees Celsius;
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg.
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg
Answer:
The metric system was originally devised so that water would have a density of 1 g/cm3, equivalent to 103 kg/m3.
<span>Alice and Tom will reach the surface of the lake at the same time.
In this problem. Both Alice and Tom have 2 components to their velocities. A horizontal component and an increasing vertical component due to gravity. They start out with different horizontal components, but that component does not in any way contribute to their vertical velocities. Since they both started out at the same height and the same vertical velocities, they will reach the surface of the lake at the same time.</span>
