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weeeeeb [17]
3 years ago
7

A ping-pong ball is traveling at 10m/s in air, spinning 100 revolutions per second in the clockwise direction. Calculate the lif

t and the drag force and indicate the direction of the lift (up or down). The ball’s diameter is 3cm and the density of air is 1.2 kg/m 3 .
Physics
1 answer:
allsm [11]3 years ago
5 0

Answer:

lift force = 0.213 N

Drag force =2*10^-3 N

Explanation:

Given: velocity v = 10 m/s

w = 100 rev/sec

diameter d = 3cm

density D = 1.2kg/m3

lift force =16/3*(pi^2*d^3*w*D*v)

Substituting the values into the equation, we obtain

lift force = 0.213 N

Drag force = C*D*A*v/2

where C = 0.5

substituting the values into the equation again, we have

Drag force =2*10^-3 N

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The answer would be 371.16 ft.


Refer to the diagram for the scenario. The drawing is not to scale.


Notice the diagram that you will find to adjacent right triangles. All you need to do is first solve for the needed side of one triangle, by using one side.


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351.16ft + 20 ft = 371.16ft

<em>The building across the street is 371.16 ft tall.</em>

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