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3 years ago

7

A ping-pong ball is traveling at 10m/s in air, spinning 100 revolutions per second in the clockwise direction. Calculate the lif

t and the drag force and indicate the direction of the lift (up or down). The ball’s diameter is 3cm and the density of air is 1.2 kg/m 3 .

1 answer:

allsm [11]3 years ago

5 0

Answer:

lift force = 0.213 N

Drag force = $2*10^-3 N$

Explanation:

Given: velocity v = 10 m/s

w = 100 rev/sec

diameter d = 3cm

density D = 1.2kg/m3

lift force = $16/3*(pi^2*d^3*w*D*v)$

Substituting the values into the equation, we obtain

lift force = 0.213 N

Drag force = C*D*A*v/2

where C = 0.5

substituting the values into the equation again, we have

Drag force = $2*10^-3 N$

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