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Vsevolod [243]
3 years ago
10

Alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running

start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. alice and tom dive from an overhang into the lake below. tom simply drops straight down from the edge, but alice takes a running start and jumps with an initial horizontal velocity of 25 m/s. neither person experiences any significant air resistance. compare the time it takes each of them to reach the lake below. tom reaches the surface of the lake first. alice reaches the surface of the lake first. alice and tom will reach the surface of the lake at the same time.
Physics
1 answer:
svetlana [45]3 years ago
3 0
<span>Alice and Tom will reach the surface of the lake at the same time. In this problem. Both Alice and Tom have 2 components to their velocities. A horizontal component and an increasing vertical component due to gravity. They start out with different horizontal components, but that component does not in any way contribute to their vertical velocities. Since they both started out at the same height and the same vertical velocities, they will reach the surface of the lake at the same time.</span>
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two identical springs of spring constant 7580 N/m are attached to a block of mass 0.245 kg. What is the frequency of oscillation
ad-work [718]

The frequency of oscillation on the frictionless floor is 28 Hz.

<h3>Frequency of the simple harmonic motion</h3>

The frequency of the oscillation is calculated as follows;

f = (1/2π)(√k/m)

where;

  • k is the spring constant
  • m is mass of the block

f = (1/2π)(√7580/0.245)

f = 28 Hz

Thus, the frequency of oscillation on the frictionless floor is 28 Hz.

Learn more about frequency here: brainly.com/question/10728818

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3 0
1 year ago
How much work does the electric field do in moving a proton from a point with a potential of +145 v to a point where it is -55 v
Aleks04 [339]
The work done by the electric field in moving a charge is the negative of the potential energy difference between the two locations, which is the product between the magnitude of the charge q and the potential difference \Delta V:
W=-\Delta U=-q\Delta V=-q (V_f -V_i)
The proton charge is q=1.6 \cdot 10^{-19}C, and the two locations have potential of V_i = +145 V and V_f=-55 V, therefore the work is
W=-(1.6 \cdot 10^{-19}C)(-55 V-(+145 V))=3.2 \cdot 10^{-17}J
5 0
2 years ago
A sound wave has a wavelength of 15 meters with a frequency of 2.5 Hz. What would the velocity be for this situation in
rodikova [14]

Answer:

6m/s

Explanation:

V = frequency * wavelength

15 * 2.5 = 6m/s

7 0
2 years ago
The strength of the electric field at a certain distance from a point charge is represented by E. What is the strength of the el
LUCKY_DIMON [66]

Answer:

e.)At twice the distance, the strength of the field is E/4.

Explanation:

The strength of the electric field at a certain distance from a point charge is given by:

E=k\frac{Q}{r^2}

where

k is the Coulomb's constant

Q is the charge

r is the distance from the point charge

In this problem, the distance from the point charge is doubled:

r' = 2r

So the new electric field strength is

E'=k\frac{Q}{(2r)^2}=k \frac{Q}{4 r^2}=\frac{1}{4} (k\frac{Q}{r^2})=\frac{E}{4}

so, at twice the distance the strength of the field is E/4.

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3 years ago
The strength of the gravitational pull between two object's is determined by?
iogann1982 [59]
Mass and distance are the two factors
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3 years ago
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