Answer:
0.25
Step-by-step explanation:
Given that a recently married couple are planning to have four children. They are equally likely to have a boy as well as a girl.
Let X be the no of boys the couples have. X has two outcomes with p = 0.5
X is binomial with n = no of trials = 4 and p =0.5
the probability that they will have three boys and one girl
=
Reqd prob = 0.25
Transformations:
1.) The -4 moves your y-intercept down 4 units. Without the -4, your y-intercept would be (0,-1)
2.) The -2 in the fraction moves your x-intercept to the to the right 2 units. Without the -2, your x-intercept would be (1/2,0)
Domain:
(-∞,2) ∪ (2,∞)
Range:
(-∞,-4) ∪ (-4,∞)
Vertical Asymptote:
x=2
Horizontal Asymptote:
y=-4
X-Intercept:
(5/2,0)
Y-Intercept:
(0,-5)
<h2>
Answer:</h2><h2>
The quotient when 69.54 is divided by 7.6 is 9.15</h2>
Step-by-step explanation:
We have to divide, 69.54 by 7.6
Therefore, the quotient is 9.15 with remainder 0
To check the answer, multiply 9.5 by 7.6, we get the product as 69.54
Therefore, the quotient when 69.54 is divided by 7.6 is 9.15
