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labwork [276]
3 years ago
7

Consider the net of a triangular prism where each unit on the coordinate plane represents ten feet. If a can of spray paint cove

rs 50 square feet, how many cans of spray paint are needed to paint the outside of the prism red?
A) 8 cans
B) 10 cans
C) 12 cans
D) 15 cans
Mathematics
2 answers:
____ [38]3 years ago
3 0
Where's the net. We need the net to answer the question
Flura [38]3 years ago
3 0
A. 8 i know the answer because i have the net right now
You might be interested in
Which reaction describes a beta emission?  2659Fe→ 2759Co +  −10e  88226Ra→ 86222Rn +  24He ��94239Pu +  24He→ 96242Cm  +  01n  
shepuryov [24]

Correct question:

Which reaction describes a beta emission?  2659Fe→ 2759Co +  −10e,   88226Ra→ 86222Rn +  24He, 94239Pu +  24He→ 96242Cm  +  01n,  54118Xe→ 53118I +  +10e

Answer:

2659Fe→ 2759Co + 1e

Step-by-step explanation:

General equation for beta decay is given as;

^A_zX -> \ ^A_{z+1}Y +\  ^0_{-1} \beta

where;

A is the atomic mass of the element

z is atomic number of the element

X is the parent atom

Y is the daughter element

β is beta emission

In beta emission, there is loss of one electron and zero proton, the will cause the daughter element to gain on electron in order to balance the reaction.

Based on beta decay equation above, we select the reaction that describes beta emission.

2659Fe→ 2759Co + 1e

Here;

A = 59

z = 26

z + 1 = 27

5 0
3 years ago
Read 2 more answers
Let the (x; y) coordinates represent locations on the ground. The height h of
grigory [225]

The critical points of <em>h(x,y)</em> occur wherever its partial derivatives h_x and h_y vanish simultaneously. We have

h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5

Substitute <em>y</em> in the second equation and solve for <em>x</em>, then for <em>y</em> :

2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}

This is to say there are two critical points,

(x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)

To classify these critical points, we carry out the second partial derivative test. <em>h(x,y)</em> has Hessian

H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}

whose determinant is 192y-16. Now,

• if the Hessian determinant is negative at a given critical point, then you have a saddle point

• if both the determinant and h_{xx} are positive at the point, then it's a local minimum

• if the determinant is positive and h_{xx} is negative, then it's a local maximum

• otherwise the test fails

We have

\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0

while

\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0

So, we end up with

h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%5Csqrt%7B2%7D%20-%205%20%5Csqrt%7B18%7D" id="TexFormula1" title="3\sqrt{2} - 5 \sqrt{18}" al
Gennadij [26K]
Here is the answer, I couldn’t type it out so I took a picture of it, if you need the steps please let me know

6 0
4 years ago
Construction company needs to remove 30 tons of dirt from the construction site they can remove 3/5 tons of dirt each hour How l
luda_lava [24]

Answer:

30t-x

3/5t=1hour

30 \times  \frac{5}{3}  = 50

they need 50hours

5 0
3 years ago
The graph of g(x) is the graph f(x)=5x+15 compressed horizontally by a factor of 1/5. What is the function of g?
andreev551 [17]
To compress horizontally means you multiply the scale factor by "x"
g(x) = 5(\frac{1}{5} x) + 15 =x+15
5 0
3 years ago
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