Complete Question
An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?
Answer:
The magnetic field strength is
Explanation:
The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression
Making v the subject
Where m is the mass of electron
v is the velocity of electron
q charge on electron
is the potential difference
Substituting values
f
For the electron to move in a circular path the magnetic force[] must be equal to the centripetal force[
] and this is mathematically represented as
making B the subject
r is the radius with a value = 5.4cm =
Substituting values