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3 years ago

Translate the following statement into a mathematical equation: The product of four and a number, plus six, is eighteen.

2 answers:

7 0

Product = multiplication

product of four and a number = 4n

plus six = + 6

'is' indicates an equal sign

So we have:

4n + 6 = 18

or B

STatiana [176]3 years ago

4 0

Answer:

4n + 6 = 18

4n + 6 = 18 -----------> b

hopes this helps

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Help me solve this please .

lord [1]

x = 59

3x - 33 = 2x + 26

-2x -2x

1x - 33 = 26

+33 +33

1x = 59

----- -----

1 1

x = 59

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3 years ago

What is 5 divided by 3,678

sergeinik [125]

Answer:

Simple division..

divide 5 by 3,678

you'll get answer

0.00135943447

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3 years ago

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In the figure, a square is inside another bigger square.

evablogger [386]

Answer:

Part 1) The length of the diagonal of the outside square is 9.9 units

Part 2) The length of the diagonal of the inside square is 7.1 units

Step-by-step explanation:

step 1

Find the length of the outside square

Let

x -----> the length of the outside square

c ----> the length of the inside square

we know that

$x=a+b=4+3=7\ units$

step 2

Find the length of the inside square

Applying the Pythagoras Theorem

$c^{2}= a^{2}+b^{2}$

substitute

$c^{2}= 4^{2}+3^{2}$

$c^{2}=25$

$c=5\ units$

step 3

Find the length of the diagonal of the outside square

To find the diagonal Apply the Pythagoras Theorem

Let

D -----> the length of the diagonal of the outside square

$D^{2}= x^{2}+x^{2}$

$D^{2}= 7^{2}+7^{2}$

$D^{2}=98$

$D=9.9\ units$

step 4

Find the length of the diagonal of the inside square

To find the diagonal Apply the Pythagoras Theorem

Let

d -----> the length of the diagonal of the inside square

$d^{2}= c^{2}+c^{2}$

$d^{2}= 5^{2}+5^{2}$

$d^{2}=50$

$d=7.1\ units$

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3 years ago

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Dmitry [639]

4,390 is the answer
I hope I helped!

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3 years ago

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A.y-2x=6<br> B.y-2x=5 <br> C.y-3x=5<br> D.y-x=5

zubka84 [21]

Answer:

B. y - 2x = 5

Step-by-step explanation:

Add 2x to both sides, and the equation becomes, y = 2x + 5, as demonstrated from the graph.

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3 years ago