PLEASE DONT SKIP THIS I NEED HELP Can someone please explain how to solve this problem?
1 answer:
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<h3>I'm solving it using substitution method:-</h3><h3>7x+2y=3 {given}</h3><h3>=>7x=3-2y</h3><h3>=>x=(3-2y)/7-------(1)</h3><h3>x-3y=30 {given}</h3><h3>=>x=30+3y</h3><h3>=>(3-2y)/7=30+3y {putting the value of x from eqn 1}</h3><h3>=>3-2y=210+21y</h3><h3>=>3-210=21y+2y</h3><h3>=>-207=23y</h3><h3>=>y= -207/23= -9</h3><h3>putting the value of y on eqn(1):-</h3><h3>x=(3-2y)/7</h3><h3>x=>(3-2(-9))/7=(3+18)/7=21/7=3</h3><h2>Hence, x=3, y= -9</h2>✌️✌️❤️❤️
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Distribute
Combine like terms
Add 1 and subtract 6x from each side
0 = 12
The equation has no real solution
Answer:
Amount invested at 8 % rate = x = $ 15000
Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000
Step-by-step explanation:
Total Amount = $ 34000
Let amount invested at 8 % rate = x
Amount invested at 9 % rate = $ 34000 - x
Total interest = $ 2910
291000 = 8 x + 306000 - 9 x
x = 306000 - 291000
x = 15000
So amount invested at 8 % rate = x = $ 15000
Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000