Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
I think it is 50, the first one, you will count 6, on each link 4 more is added so when adding 11 more links it would be 44+6 which is 50
Um idk sorry lol that’s way to hard for me
Hopes this helps:
Answer: 2
1•3+1/3 divided 2/3
3+1/3 divided 2/3
4/3 divided 2/3
4/3 • 3/2
4 • 1/2
4/2
2
16 is the answer jxhsjcjaks