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vazorg [7]
3 years ago
9

The blanks and examples for these properties

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Commutative - ORDER doesn't matter. ex. 5+7 = 7+5

Associative - GROUPING of values doesn't matter. ex. (7 +/* 2) + 4 = 7 +/* (2 + 4)

Identity - Anything added to ZERO is the original number. Anything multiplied by 1 is the original number. ex. 4 + 0 = 4 * 1 = 4

Inverse - Using the OPPOSITE to cancel the terms. ex. a + (-a) = (-a) + a = 0    

a * 1/a = 1/a * a = 1  (if a ≠ 0)

Zero - Multiplying by ZERO, always equals ZERO.  ex. 4 * 0 = 0

Distributive - Distribute a value outside the parenthesis to all values inside the parenthesis. ex B(A+Y) = BA + BY


Hope this helps! :)

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Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

  • x_{1f} +x_{2f} =3

5) Substitute the values we already know

  • 1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0
3 years ago
Helpppppppppppppppppp​
UNO [17]

Answer:

<em>2 solutions</em>

Step-by-step explanation:

Given the expression

2m/2m+3 - 2m/2m-3 = 1

Find the LCM of the expression at the left hand side:

2m(2m-3)-2m(2m+3)/(2m+3)(2m-3) = 1

open the bracket

4m²-6m-4m²-6m/(4m²-9) = 1

Cross multiply

4m²-6m-4m²-6m = 4m²  - 9

-12m = 4m²  - 9

4m²  - 9+12m = 0

4m² +12m-9 = 0

<em>Since the resulting equation is a quadratic equation, it will have 2 solutions since the degree of the equation is 2</em>

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What is the missing fact in this fact family 7+5 =12 , 12-5=7 , 12-7=5
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Missing fact is 13 seats are empty
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Answer : 1 3/5 yds
I’m not sure I’d check it
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