All categories

3 years ago

Pierce works at a tutoring center on the weekends.

Mathematics

2 answers:

NeX [460]3 years ago

8 0

Answer:

504 millimeters (or 50.4 cm)

Step-by-step explanation:

Width of key in student calculator = 14 millimeter (1.4 cm)

Width of key in demonstration calculator = 2.8 cm

Thus, the demonstration calculator's dimensions are twice that of students' (in cm)

Also given, student calculator height as 252 millimeters (25.2 cm)

Thus demonstration calculator height will be twice of that = 50.4 cm (or 504 millimeters)

Arturiano [62]3 years ago

4 0

Answer:

I got 0.494 meter!

Step-by-step explanation:

First, set up a proportion to find the height of the demonstration calculator in centimeters.

Next, convert 49.4 centimeters to meters.

Therefore, the demonstration calculator is 0.494 meter tall.

You might be interested in

Hello I hope you have a wonderful day can you pls help me out it I will fail

ASHA 777 [7]

A. Independent goes on the x axis and dependent goes on the y axis
B. It shows his or hers miles per hour or mph or distance they run in a hour

Hope this helps have a great Monday ❤️

5 0

3 years ago

The perimeter of a rectangle is 42 inches, and its area is 110 square inches. find the length and width of the rectangle.

lorasvet [3.4K]

$p = 2w + 2l$ $p = 42$
$a = l * w$ $a = 108$

You want to make either the length or width variable (I chose the width variable to be by itself. It doesn't matter) by itself by:

Divide both sides by 2.
(p) ÷ 2 = (2w + 2l) ÷ 2
$2's$ $cancel$ $out$
$\frac{p}{2} = w + l$

Subtract both sides by either length or width depending on what variable you chose to make by itself (in this case I subtracted the length variable because I wanted the width variable by itself).
$\frac{p}{2} - l = w + l - l$
$l's$ $cancel$ $out$
p/2 - l = w

$a = l * w$

You replace w with the equation above p/2 - l = w
$a = l( \frac{p}{2} - l)$

Multiply out the L.
$a = \frac{p}{2}l - l^{2}$

Plug in all your numbers a = 110 and p = 42
$110 = \frac{42}{2}l - l^{2}$
$110 = 21l - l^{2$

Move everything to the left side so $l^{2}$ would be positive (makes the equation easier when $l^{2}$ is positive).
$l^{2} - 21l + 110 = 0$

Factor.
$(l -10)(l-11) = 0$

Make each parenthesis set equal to 0.
$l-11=0$ $l-10=0$

Add.
$l = 11$ $l = 10$

By doing this you solve for both the width and length so the answer is:
w = 11 L = 10

8 0

3 years ago

Factor the equation 8y-36

musickatia [10]

4(2y−9) is the correct answer

6 0

3 years ago

A car travels down a highway at 25 m/s. An observer stands 150 m from the highway.

makvit [3.9K]

Let x be the distance (in feet) along the road that the car has traveled and h be the distance (in feet) between the car and the observer.

(a) Before the car passes the observer, we have dh/dt < 0; after it passes, we have dh/dt > 0. So at the instant it passes the observer we have dh/dt = 0, given that dh/dt varies continuously since the car travels at a constant velocity.

8 0

3 years ago

What two products do you get when you cross-multiply the fractions 2/5 and 3/8?

jarptica [38.1K]

Answer: a. 10 and 12

explanation:

4 0

3 years ago