A. Jenna because an optimistic person always has a healthier look in life!
Answer:
sound water because sound is the most important electronic wave for water
The periodic table shows the atomic number ( # of protons) and average atomic mass (weight of protons and neutrons combined). You can subtract the number of protons from the atomic mass of that element to find number of neutrons.
So the area under a velocity time graph is distance or displacement, if you have done calculus yet you will understand that if you take the integral of a velocity function then you end up with displacement. Thats for later understanding however.
So this appears to be a right triangle so we can find the area of a triangle as:
0.5bh = A
Since our area is 10 meters lets alter our formula a bit to fit the situation:
Our base here is time and our height is velocity so:
0.5tv = Δx
So we can read off the graph that our velocity at the end, or our final velocity appears to be near 2.0 m/s
So we have v, and Δx so lets isolate for time by dividing by v and 0.5
t = Δx / 0.5v
Now lets plug all that in:
t = 10 / 0.5(2)
t = 10 seconds
Hope this helped!
Complete Question
A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?
Answer:
The values is ![E =248.2 \ N/C](https://tex.z-dn.net/?f=E%20%3D248.2%20%5C%20%20N%2FC)
Explanation:
From the question we are told that
The diameter is ![d = 12 \ cm = 0.12 \ m](https://tex.z-dn.net/?f=d%20%3D%20%2012%20%5C%20%20cm%20%20%3D%20%200.12%20%5C%20m)
The charge is ![Q = 4.4 nC = 4.4 *10^{-9} \ C](https://tex.z-dn.net/?f=Q%20%3D%20%204.4%20nC%20%20%3D%20%204.4%20%2A10%5E%7B-9%7D%20%5C%20%20C)
The distance from the center is ![k = 0.1 \ mm = 1*10^{-4} \ m](https://tex.z-dn.net/?f=k%20%3D%20%200.1%20%5C%20mm%20%20%20%3D%20%201%2A10%5E%7B-4%7D%20%5C%20%20m)
Generally the radius is mathematically represented as
![r = \frac{d}{2}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Cfrac%7Bd%7D%7B2%7D)
=> ![r = \frac{0.12}{2}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Cfrac%7B0.12%7D%7B2%7D)
=> ![r = 0.06 \ m](https://tex.z-dn.net/?f=r%20%3D%20%200.06%20%5C%20%20m)
Generally electric field is mathematically represented as
![E = \frac{Q}{ 2\epsilon_o } [1 - \frac{k}{\sqrt{r^2 + k^2 } } ]](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7BQ%7D%7B%202%5Cepsilon_o%20%7D%20%5B1%20-%20%5Cfrac%7Bk%7D%7B%5Csqrt%7Br%5E2%20%2B%20%20k%5E2%20%7D%20%7D%20%5D)
substituting values
![E = \frac{4.4 *10^{-9}}{ 2* (8.85*10^{-12}) } [1 - \frac{(1.00 *10^{-4})}{\sqrt{(0.06)^2 + (1.0*10^{-4})^2 } } ]](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7B4.4%20%2A10%5E%7B-9%7D%7D%7B%202%2A%20%288.85%2A10%5E%7B-12%7D%29%20%7D%20%5B1%20-%20%5Cfrac%7B%281.00%20%2A10%5E%7B-4%7D%29%7D%7B%5Csqrt%7B%280.06%29%5E2%20%2B%20%20%281.0%2A10%5E%7B-4%7D%29%5E2%20%7D%20%7D%20%5D)
![E =248.2 \ N/C](https://tex.z-dn.net/?f=E%20%3D248.2%20%5C%20%20N%2FC)