Ask question

Ask question

All categories

2 years ago

13

What does it mean when we say two objects are in equilibrium

1 answer:

cupoosta [38]2 years ago

8 0

An object is considered to be in a condition of equilibrium when it is balanced with regard to all external forces.

Equilibrium:

An object is considered to be in equilibrium if both its angular acceleration and the acceleration of its center of mass are equal to zero. In layman's terms: The item must either be at rest or moving at a constant speed if it is not accelerating because F = ma (force = mass x acceleration). Even in motion, a body can be in equilibrium. This kind of equilibrium is referred to as a dynamic equilibrium.

A weight suspended by a spring or a brick laying on a flat surface is an example. The equilibrium is unstable if the force with the smallest deviation tends to increase the displacement. As an example, imagine a ball bearing on the edge of a razor blade.

Learn more about equilibrium here:

brainly.com/question/13153118

#SPJ1

You might be interested in

Ok rlly guys help me

garik1379 [7]

Moving clouds. The doppler effect is specifically used to measure motion.

5 0

3 years ago

Read 2 more answers

A satellite orbiting above the earth needs no power source to keep orbiting the earth.

abruzzese [7]

Answer:

True

Explanation:

The earths gravitational pull keeps it consistent with its orbit.

8 0

3 years ago

Read 2 more answers

If E = mc^2 then what does c = ?

scoundrel [369]

E = Energy m = Mass c = Speed of light.

4 0

3 years ago

Read 2 more answers

A spherical snowball is melting in such a way that its radius is decreasing at a rate of 0.1 cm/min. At what rate is the volume

Ne4ueva [31]

Answer: 80.384 cubic cm /min

Explanation:

Let V denote the volume and r denotes the radius of the spherical snowball .

Given : $\dfrac{dr}{dt}=-0.1\text{cm/min}$

We know that the volume of a sphere is given by :-

$V=\dfrac{4}{3}\pi r^3$

Differentiating on the both sides w.r.t. t (time) ,w e get

$\dfrac{dV}{dt}=\dfrac{4}{3}\pi(3r^2)\dfrac{dr}{dt}\\\\\Rightarrow\ \dfrac{dV}{dt}=4\pi r^2 (-0.1)=-0.4\pi r^2$

When r= 8 cm

$\dfrac{dV}{dt}=-0.4(3.14)(8)^2=-80.384$

Hence, the volume of the snowball decreasing at the rate of 80.384 cubic cm /min.

6 0

3 years ago

The speed of sound in air is 320 ms-1 and in water it is 1600 ms-1. It takes 2.5 s for sound to reach a certain distance from th

Nonamiya [84]

Answer:

Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.

Explanation:

Given:

Speed of sound in air = 320 m/s

Speed of sound in water = 1600 m/s

Time taken to reach certain distance in air = 2.5 sec

a.

We have to find the distance traveled by sound in air.

Distance = Product of speed and time.

⇒ $Distance = Speed\times time\ taken$

⇒ $Distance = 320\times 2.5$

⇒ $Distance = 800$ meters.

b.

Now we have to find how much time the sound will take to travel in water.

⇒ Time = Ratio of distance and speed

⇒ $Time =\frac{distance}{speed}$

⇒ $Time =\frac{800}{1600}$ <em> ...distance = 800 m and speed = 1600 m/s</em>

⇒ $Time =\frac{1}{2}$

⇒ $Time =0.5$ seconds.

Distance covered by the sound in air is 800 meter and the time taken by the sound in water for the same distance is 0.5 seconds.

7 0

3 years ago