Answer:
The dimension is 
Explanation:
From the question we are told that

Here ![[J] = \frac{1}{L^2 T}](https://tex.z-dn.net/?f=%5BJ%5D%20%3D%20%5Cfrac%7B1%7D%7BL%5E2%20T%7D)
![[n] =\frac{1}{L^3}](https://tex.z-dn.net/?f=%5Bn%5D%20%3D%5Cfrac%7B1%7D%7BL%5E3%7D)
![[x] = L](https://tex.z-dn.net/?f=%5Bx%5D%20%3D%20L)
So
![\frac{1}{L^2 T} = -D \frac{d(\frac{1}{L^3})}{d[L]}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BL%5E2%20T%7D%20%3D%20%20-D%20%5Cfrac%7Bd%28%5Cfrac%7B1%7D%7BL%5E3%7D%29%7D%7Bd%5BL%5D%7D)
Given that the dimension represent the unites of n and x then the differential will not effect on them
So
=> 
=> 
"Describing how copper changes color in chlorine" is the answer I think is right. Hope this helped!
In other words a infinitesimal segment dV caries the charge
<span>dQ = ρ dV </span>
<span>Let dV be a spherical shell between between r and (r + dr): </span>
<span>dV = (4π/3)·( (r + dr)² - r³ ) </span>
<span>= (4π/3)·( r³ + 3·r²·dr + 3·r·(dr)² + /dr)³ - r³ ) </span>
<span>= (4π/3)·( 3·r²·dr + 3·r·(dr)² + /dr)³ ) </span>
<span>drop higher order terms </span>
<span>= 4·π·r²·dr </span>
<span>To get total charge integrate over the whole volume of your object, i.e. </span>
<span>from ri to ra: </span>
<span>Q = ∫ dQ = ∫ ρ dV </span>
<span>= ∫ri→ra { (b/r)·4·π·r² } dr </span>
<span>= ∫ri→ra { 4·π·b·r } dr </span>
<span>= 2·π·b·( ra² - ri² ) </span>
<span>With given parameters: </span>
<span>Q = 2·π · 3µC/m²·( (6cm)² - (4cm)² ) </span>
<span>= 2·π · 3×10⁻⁶C/m²·( (6×10⁻²m)² - (4×10⁻²m)² ) </span>
<span>= 3.77×10⁻⁸C </span>
<span>= 37.7nC</span>
<h2>
Answer: Earth's orbital path around the Sun</h2><h2>
</h2>
The <u>Ecliptic</u> refers to the orbit of the Earth around the Sun. Therefore, <u>for an observer on Earth it will be the apparent path of the Sun in the sky during the year, with respect to the "immobile background" of the other stars.</u>
<u />
It should be noted that the ecliptic plane (which is the same orbital plane of the Earth in its translation movement) is tilted with respect to the equator of the planet about
approximately. This is due to the inclination of the Earth's axis.
Hence, the correct option is Earth's orbital path around the Sun.
5.6 which would be acidic!