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3 years ago

11

When a wool cloth is rubbed on the surface of a balloon, it tends to give away electrons causing the surface of the balloon to b

ecome_______.

2 answers:

babunello [35]3 years ago

3 0

Answer:

Is there Any Choices?

Explanation:

zepelin [54]3 years ago

3 0

Answer:

yeah guys no trolls step by step explanation

Explanation:

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Nana76 [90]

What's is the question asking, true or false?

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3 years ago

Select the correct expression that gives the block's acceleration at a displacement x from the equilibrium position. Note that x

Tcecarenko [31]

Answer:

the correct is d

a= - k/m x

Explanation:

I got it correct

6 0

4 years ago

Net force is the sum of all the forces acting on an object. If a spring balance pulls on a body with a force of 10 N, and fricti

julsineya [31]

Answer:

5N

Explanation:

(25 N - 20 N = 5 N)

3 0

4 years ago

A fire hose has an inside diameter of 6.40 cm. Suppose such a hose carries a flow of 40.0 L/s starting at a gauge pressure of 1.

inessss [21]

Answer:

The Reynolds numbers for flow in the fire hose.

Explanation:

Given that,

Diameter = 6.40 cm

Rate of flow = 40.0 L/s

Pressure $P=1.62\times10^{6}\ N/m^2$

We need to calculate the Reynolds numbers for flow in the fire hose

Using formula of rate of flow

$Q=Av$

$v=\dfrac{Q}{A}$

Where, Q = rate of flow

A = area of cross section

Put the value into the formula

$v=\dfrac{40.0\times10^{-3}}{3.14\times(3.2\times10^{-2})^2}$

$v=12.44\ m/s$

We need to calculate the Reynolds number

Using formula of the Reynolds number

$n_{R}=\dfrac{2\rho\times v\times r}{\eta}$

Where, $\eta$ =viscosity of fluid

$\rho$ =density of fluid

Put the value into the formula

$n_{R}=\dfrac{2\times100\times12.44\times3.2\times10^{-2}}{1.002\times10^{-3}}$

$n_{R}=7.945\times10^{5}$

Hence, The Reynolds numbers for flow in the fire hose.

3 0

3 years ago

Suppose a conducting rod is 52 cm long and slides on a pair of rails at 2.75 m/s. What is the strength of the magnetic field in

Eva8 [605]

Answer:

5.6 Tesla

Explanation:

L = 52 cm = 0.52 m

V = 2.75 m/s

e = 8 V

Let B be tha magnitude of magnetic field. Use the formula for the motional emf

e = B × V × L

B = e / V L

B = 8 / (2.75 × 0.52)

B = 5.6 Tesla

6 0

4 years ago