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Misha Larkins [42]
3 years ago
8

What three characteristics do geologist look for when observing a rock sample

Physics
2 answers:
lord [1]3 years ago
5 0
Texture hardness and color
lara [203]3 years ago
5 0
The hardness of the rocks texture and the color of the rock.
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Two positive point charges repel each other with force 0.36 N when their separation is 1.5 m. What force do they exert on each o
egoroff_w [7]
The answer is: 0.81

I hope this helps :)
6 0
3 years ago
Which statement accurately describes impulse?<br> State corrrect answer from the choices
zhuklara [117]

Answer:

5354..

Explanation:

6 0
2 years ago
In addition to an all-round white light, what light(s) must power-driven vessels less than 65.6 feet (20 meters) long exhibit wh
Lemur [1.5K]
The vessel must also have red and green side lights.

The red light is placed on the port (left) side of the boat while the green light is placed on the starboard (right) side of the vehicle. The white lights are on both the masthead (front) and stern (rear) of the boat, unless the vessel is less than 39.4 feet, in which case the front and rear white light may be combined as only one white light.
7 0
3 years ago
Read 2 more answers
Rock X is released from rest at the top of a cliff that is on Earth. A short time later, Rock Y is released from rest from the s
MArishka [77]

Answer:

<h2>D) S increases because at all times Rock X falls with a greater speed than Rock Y</h2>

Explanation:

As we know that Stone X is dropped first and then after some time stone Y is dropped

Now we have

v_x = gt_1

similarly for Y

v_y = g(t_1 - \Delta t)

now the relative acceleration of two stones while they are in air is ZERO

also we know from above equations

v_x > v_y

so the separation between two stones will keep on increasing as the speed of X is more than the speed of Y

5 0
3 years ago
Please help me with this very easy question I just don’t get it.
diamong [38]

Answer:

150m

Explanation:

The relation of speed/time and distance/time is a derivative/integral one, as in speed is the derivative of distance (the faster you go, the faster the distance changes, duh!).

So we need to compute the integral of speed over time from 0.0s to 5.0s.

The easiest way here is to compute the area under the line (it's going to be faster than computing the acceleration and using a formula of distance based on acceleration).

The area under the line is a trapezoid with "height" 5s, and the bases 10m/s and 50m/s. Using the trapezoid area formula of h*(a + b)/2

distance = 5s * (10m/s + 50m/s) / 2 = 5s * 60m/s / 2 = 5s * 30m/s = 150m

Alternatively, we can use the acceleration formula:

a = (50m/s - 10m/s)/5s = 40m/s / 5s = 8m/s^2

distance = v0 * t + a * t^2 / 2 = 10m/s * 5s + 8m/s^2 * (5s)^2 / 2 = 50m + 8m * 25 / 2 = 50m + 100m = 150m.

5 0
2 years ago
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