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mihalych1998 [28]
3 years ago
14

A 8.46 L sample oxygen gas at 267K and 1.23 atm is heated to 295K. If the volume changes to 6.98L, what is the new pressure?

Chemistry
1 answer:
horrorfan [7]3 years ago
7 0

Answer:

The new pressure is 1,65 atm

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T.

(P1xV1)/T1= (P2xV2)/T2

(1,23atmx 8,46L)/267 K = (P2 x 6,98L)/ 295K

0,039 atmx L/K = (P2 x 6,98L)/ 295K

P2=(0,039 atmx L/K)x 295K/6,98L =1,65 atm

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Consider the following reaction:
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Answer:

Explanation:

                  Fe + Cl₂ →  FeCl₃

a. The balanced equation

    All chemical equations obey the law of conservation of matter. To balance this above equation, we either inspect or use mathematical method to obtain a balanced equation.

We put coefficients a, b and c at the back of the compounds as shown below:

                    aFe + bCl₂ →  cFeCl₃

For Fe:

      a = c                          (i)

For Cl:

     2b = 3c                        (ii)

let a = 1, c= 1

Solving for the unknown b, we have:

          b = \frac{3c}{2}

           b = \frac{3}{2}

The complete reaction equation is therefore:

            Fe + \frac{3}{2}Cl₂ →  FeCl₃

                                     or

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Problem a:

Mass of reacting iron = 25g

unknown: number of moles of iron

Solution

To find the number of moles, we apply the mole concept using the expression below:

number of moles = \frac{mass}{molar mass} \\

To find the molar mass of the reactant iron, we know atomic mass of iron is 56g.

The molar mass is therefore, 56gmol⁻¹

number of moles = \frac{25}{56} \\

number of moles of the iron reactant  = 0.45mole

Problem b:

From the balanced equation of the reaction:

             2Fe + 3Cl₂ →  2FeCl₃

      2 moles of Fe produces 2 moles of FeCl₃

     So 0.45mole of Fe would produce 0.45 mole of FeCl₃

Problem C:

Applying the mole concept;

      mass of FeCl₃ = number of moles of FeCl₃ x molar mass of FeCl₃

     number of moles of FeCl₃ = 0.45mole

     molar mass of FeCl₃ = ?

Atomic mass of Fe = 56g

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      Molar mass of FeCl₃ = 56 + (3 x 35.5) = 56 + 106.5 = 162.5gmol⁻¹

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Explanation:

Process

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                               x = 126.2 g

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