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mihalych1998 [28]
3 years ago
14

A 8.46 L sample oxygen gas at 267K and 1.23 atm is heated to 295K. If the volume changes to 6.98L, what is the new pressure?

Chemistry
1 answer:
horrorfan [7]3 years ago
7 0

Answer:

The new pressure is 1,65 atm

Explanation:

We use the gas formula, which results from the combination of the Boyle, Charles and Gay-Lussac laws. According to which at a constant mass, temperature, pressure and volume vary, keeping constant PV / T.

(P1xV1)/T1= (P2xV2)/T2

(1,23atmx 8,46L)/267 K = (P2 x 6,98L)/ 295K

0,039 atmx L/K = (P2 x 6,98L)/ 295K

P2=(0,039 atmx L/K)x 295K/6,98L =1,65 atm

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The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g
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1) When 6.97 grams of sodium(s) react with excess water(l), 56.0 kJ of energy are evolved.

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1) The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g).

2 Na(s) + 2H₂O(l) ⇒ 2NaOH(aq) + H₂(g) ΔH = -369 kJ

The enthalpy of the reaction is negative, which means that 369 kJ of energy are evolved per 2 moles of sodium. The energy evolved for 6.97 g of Na (molar mass 22.98 g/mol) is:

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