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tensa zangetsu [6.8K]
3 years ago
6

Which of the following large-scale environmental catastrophes has the least effect on aquatic ecosystems?

Chemistry
2 answers:
Trava [24]3 years ago
7 0
Deforestation has had the least effect on aquatic life.
Marta_Voda [28]3 years ago
6 0

Answer:

Deforestation.

Explanation:

Deforestation is a large-scale environmental catastrophe that does not have a great effect on the ocean's ecosystem because it does not affect it directly. Deforestation can affect the ocean's ecosystem in the long term due to the reduction of O₂ in the atmosphere, which contributes to global warming affecting the ocean's ecosystem along with pollution.

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How many moles in 0.672L of F2?
marishachu [46]

Answer:

c

Explanation:

i think if not tell me ok

3 0
3 years ago
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What is the molarity of a solution made by dissolving 8.60 g of a solid with a
Dima020 [189]

Answer:

1.43 M

Explanation:

We'll begin by calculating the number of mole of the solid. This can be obtained as follow:

Mass of solid = 8.60 g

Molar mass of solid = 21.50 g/mol

Mole of solid =?

Mole = mass / molar mass

Mole of solid = 8.60 / 21.50

Mole of solid = 0.4 mole

Next, we shall convert 280 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

280 mL = 280 mL × 1 L / 1000 mL

280 mL = 0.28 L

Thus, 280 mL is equivalent to 0.28 L.

Finally, we shall determine the molarity of the solution. This can be obtained as illustrated below:

Mole of solid = 0.4 mole

Volume = 0.28 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.4 / 0.28

Molarity = 1.43 M

Thus, the molarity of the solution is 1.43 M.

8 0
3 years ago
I need the answer by 12❤️
Alex787 [66]

Answer:

answer number 3? ac

Explanation:

8 0
3 years ago
Chlorine (Cl) forms a salt when it is combined with a metal. This element belongs in _____. group 18 group 17 period 18 period 1
Goshia [24]
Group 17 is your answer, I hope it helps you :]
4 0
4 years ago
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Radioactive carbon-14 has a half life of 5730 years. Suppose a peice of wood has a decay rate of 15 disintegrations per minute.
Tom [10]

Answer:

\large \boxed{\text{2920 yr}}

Explanation:

Two important formulas in radioactive decay are

(1) \qquad t_{\frac{1}{2}} = \dfrac{\ln 2}{k}\\\\(2) \qquad \ln \left(\dfrac{N_{0}}{N}\right) = kt

1. Calculate the decay constant k

\begin{array}{rcl}t_{\frac{1}{2}} &=& \dfrac{\ln 2}{k}\\\\\text{1530 yr} &= &\dfrac{\ln 2}{k}\\\\k & = & \dfrac{\ln 2}{\text{1530 yr}}\\\\& = & 4.530 \times 10^{-4} \text{ yr}^{-1}\\\end{array}

2. Calculate the time

\begin{array}{rcl}\ln \left(\dfrac{N_{0}}{N}\right) &= &kt \\\\\ln \left(\dfrac{15}{4}\right) &= &4.530 \times 10^{-4} \text{ yr}^{-1}\times t \\\\\ln 3.75 &= &4.530 \times 10^{-4} \text{ yr}^{-1}\times t \\t &= &\dfrac{\ln 3.75}{4.530 \times 10^{-4} \text{ yr}^{-1}}\\\\& = & \textbf{2920 yr}\\\end{array}\\\text{It would take $\large \boxed{\textbf{2920 yr}}$ for the rate to decrease to 4 dis/min.}

5 0
4 years ago
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