As the mass of a star increases the lifespan of the star

How many total atoms are in 0.680 g of P₂O5?

Ludmilka [50]

Answer: 2.88× $10^{24}$ atoms $P_{2}O_{5}$

Explanation: First, using stoichiometry, we must convert this from grams to moles, then from moles to atoms.

1. For the first step, we should also look at the periodic table to find the molar mass of the compound, then use that as the denominator.

$0.680g P_{2} O_{5} *\frac{1molP_{2} O_{5} }{141.948gP_{2} O_{5} } =4.79mol P_{2} O_{5}$

2. Now that it is converted to moles, we must convert it to atoms by multiplying it by Avogadro's number.

$4.79molP_{2} O_{5} *\frac{6.022X10^{23} }{1mol} =2.88*10^{24}$

With this information, we know that there are $2.88X10^{24}$ total atoms in 0.680 grams $P_{2} O_{5}$ .

I hope this helps! Pls give brainliest!! :)

8 0

2 years ago

In the single displacement reaction of HCl and magnesium, how many grams of magnesium chloride would be produced if 1.05g of mag

iren [92.7K]

Answer:

4.16g of MgCl2

Explanation:

First, let us generate a balanced equation for the reaction:

Mg + 2HCl —> MgCl2 + H2

Molar Mass of Mg = 24g/mol

Molar Mass of MgCl2 = 24 + (2x35.5) = 24 + 71 = 95g

From the equation,

24g of Mg produced 95g of MgCl2.

Therefore, 1.05g of Mg will produce = (1.05x95)/24 = 4.16g of MgCl2

5 0

3 years ago

Which equation represents sublimation? 2Al+3I=2AlI HgCl=HgCl

AlexFokin [52]

I guess it is the second one but you missed the state symbols.

4 0

2 years ago

Identify the oxidized and reduced forms from the following pairs:

Luden [163]

Answer:

1. NAD⁺ is the oxidized form and NADH is the reduced form

2. Pyruvate is the oxidized form and Lactate is the reduced form.

3. Oxaloacetate is the oxidized form and Malate is the reduced form.

4. Fumarate is the oxidized form and Succinate is the reduced form.

5. FMN is the oxidized form and FMNH₂ is the reduced form

6. α-ketoglutarate is the oxidized form and Isocitrate is the reduced form.

7. O₂ is the oxidized form and H₂O₂ is the reduced form.

Explanation:

Oxidation is the gain of oxygen or loss of electrons or hydrogen. Whereas, reduction is the loss of oxygen or gain of electrons or hydrogen.

1. NAD⁺/NADH

NAD⁺ is the oxidized form and NADH is the reduced form of Nicotinamide adenine dinucleotide, NAD.

Therefore, NAD⁺ gets reduced to NADH by accepting electrons and proton.

NAD⁺ + 2 e⁻ + H⁺ → NADH

2. Pyruvate/lactate

Pyruvate, CH₃COCOO⁻, is the conjugate base of Pyruvic acid.

Lactate, CH ₃CH(OH)COO⁻, is the conjugate base of Lactic acid.

Reduction of Pyruvate to lactate:

CH₃COCOO⁻ + NADH ⇌ CH ₃CH(OH)COO⁻ + NAD⁺

This reaction is catalyzed by the enzyme lactate dehydrogenase.

Therefore, Pyruvate is the oxidized form and Lactate is the reduced form.

3. Malate/oxaloacetate

Oxaloacetate, ⁻O₂CC(O)CH₂CO₂⁻, is the conjugate base of oxaloacetic acid.

Malate,⁻O₂CCH(OH)CH₂CO₂⁻, is the conjugate base of Malic acid.

Oxidation of Malate to Oxaloacetate:

⁻O₂CCH(OH)CH₂CO₂⁻ + NAD⁺ ⇌ ⁻O₂CC(O)CH₂CO₂⁻ + NADH

This reaction is catalyzed by the enzyme malate dehydrogenase.

Therefore, Oxaloacetate is the oxidized form and Malate is the reduced form.

4. Fumarate/succinate

Fumarate, ⁻O₂CCH=CHCO₂⁻, is the conjugate base of Fumaric acid.

Succinate, ⁻O₂CCH₂CH₂CO₂⁻, is the conjugate base of Succinic acid.

Oxidation of succinate to fumarate:

⁻O₂CCH₂CH₂CO₂⁻ + FAD ⇌ ⁻O₂CCH=CHCO₂⁻ + FADH₂

This reaction is catalyzed by the enzyme succinate dehydrogenase.

Therefore, fumarate is the oxidized form and succinate is the reduced form.

5. FMN/FMNH₂

FMN is the oxidized form and FMNH₂ is the reduced form of riboflavin-5′-phosphate or Flavin mononucleotide.

Therefore, FMN gets reduced to FMNH₂ by accepting electrons and proton.

FMN + 2 e⁻ + 2H⁺ → FMNH₂

6. α-ketoglutarate/isocitrate

α-ketoglutarate, ⁻O₂CC(O)CH₂CH₂CO₂⁻, is the conjugate base of α-Ketoglutaric acid.

Isocitrate, ⁻O₂CCH(OH)CH(CO₂⁻)CH₂CO₂⁻, is the conjugate base Isocitric acid.

Oxidation of Isocitrate to α-ketoglutarate:

⁻O₂CCH(OH)CH(CO₂⁻)CH₂CO₂⁻ + NAD⁺ → ⁻O₂CC(O)CH₂CH₂CO₂⁻ + CO₂ + NADH

This reaction is catalyzed by the enzyme Isocitrate dehydrogenase.

Therefore, α-ketoglutarate is the oxidized form and Isocitrate is the reduced form.

7. H₂O₂/O₂

Hydrogen peroxide, H₂O₂, is synthesized from hydrogen (H₂) and oxygen (O₂) in the presence of a catalyst.

H₂ + O₂ → H₂O₂

Oxygen gets reduced from 0 oxidation state in O₂ to -1 oxidation state in H₂O₂.

Therefore, O₂ is the oxidized form and H₂O₂ is the reduced form.

8 0

3 years ago

The partial pressure of CH4 is 0.175 atm and that of O2 is 0.250 atm in a mixture of the two gases. What is the mole fraction of

tresset_1 [31]

Answer:

The total number of moles of gas in the mixture is 0.16939.

1.25550 grams of methane gas and 3.18848 grams of oxygen gas.

Explanation:

Total volume of the mixture = V = 10.5 L

Temperature of the mixture = T = 35°C = 308.15K

Pressure of the mixture = P

Total moles of mixture = n = $n_1+n_2$

Using an ideal gas equation :

$PV=nRT$

$P\times 10.0 L=n\times 0.0821 atm L/mol K\times 308.15 K$

$P=2.509 n$

Partial pressure of the methane= $p_1=0.175 atm$

Moles of the methane= $n_1$

Partial pressure of the oxygen gas= $p_2=0.250 atm$

Moles of the methane= $n_2$

Mole fraction of the methane= $\chi_1=\frac{n_1}{n_1+n_2}$

Mole fraction of the oxygen gas= $\chi_2=\frac{n_2}{n_1+n_2}$

$p_1=p\times \chi_1$ (Dalton's law)

$0.175 atm=P\times \frac{n_1}{n_1+n_2}$

$0.175 atm=(2.509 n)\times \frac{n_1}{n}$

$n_1=0.06975 mol$

Mass of 0.06975 moles of methane gas :

0.06975 mol × 18 g/mol =1.25550 g

$p_2=p\times \chi_2$ (Dalton's law)

$0.250 atm=P\times \frac{n_2}{n_1+n_2}$

$0.250 atm=(2.509 n)\times \frac{n_2}{n}$

$n_2=0.09964 mol$

Mass of 0.06975 moles of oxygen gas :

0.09964 mol × 32 g/mol =3.18848 g

Total moles of mixture = n = $n_1+n_2$

[/tex]=0.06975 mol+0.09964 mol=0.16939 mol[/tex]

7 0

3 years ago