I answered that in your last question refer to your answer in section 2
Answer:
Density can be useful in identifying substances. It is also a convenient property because it provides a link (or conversion factor) between the mass and the volume of a substance. Mass and volume are extensive (or extrinsic) properties of matter - they depend on amount.
Explanation:
Technically, there are an infinite number of possible amino acids, though we've found only 20 common ones that many organisms use and at least half a dozen obscure ones that specific organisms use. We focus only on the 20 common ones unless we're in a college level biochemistry course.
The three categories are nonpolar ones, polar ones, and charged ones. The nonpolar ones have non-polar side chains (no oxygens or nitrogens), the polar ones have polar side chains (most contain an OH group but no COOH group), the charged ones are either acidic or basic (has COOH group or a basic nitrogen).
Addition of water to an alkyne gives a keto‑enol tautomer product and that is the product changed into 2-pentanone, then the alkyne need to had been 1-pentyne. 2-pentyne might have given a combination of 2- and 3-pentanone.
<h3>
What is the keto-enol means in tautomer?</h3>
They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.
- The enol that could provide 2-pentanone might had been pent-1- en - 2 -ol. Because an equilibrium favors the ketone so greatly, equilibrium isn't an excellent description.
- If the ketone have been handled with bromine, little response might be visible because the enol content material might be too low.
- If a catalyst have been delivered, NaOH for example, then formation of the enolate of pent-1-en - 2 - ol might shape and react with bromine.
- This might finally provide a bromoform product. Under acidic conditions, the enol might desire formation of the greater substituted enol constant with alkene stability.
Answer: Mass of the condensed vapor is 21.35 grams.
Explanation: As a gas, the Ideal Gas Law can be used to determine how many mols there are in the flask on the conditions described in question.
Temperature in K: 273 + 99.3 = 372.4K
Pressure in mmHg: P = 760.5 mmHg
Volume in L: V = 496.3.
= 0.5 L
Universal Constant of Gases in mmHg: R = 62.36 L.mmHg.K⁻¹.mol⁻¹
PV = nRT
n = 
n = 
n = 0.1625
To determine the mass in grams:
n = 
m = nM
m = 0.1625.131.4
m = 21.35
On the conditions cited above, there are <u>21.35 grams</u> of the unknown condensed vapor
