Yes you can it will not just have 5 :)
Answer:
(3R,4R)-4-bromohexan-3-ol
Explanation:
In this case, we have reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.
Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)
I hope it helps!
Answer:
Li⁺
Explanation:
Li⁺ ions has a noble gas electron configuration because it resembles that of He.
To have a noble configuration, electrons in the outermost shell must completely fill their respective orbitals.
Li⁺ is an ion that has lost one electron from the usual number of 3 thereby remaining 2 electrons.
The electronic configuration is given as;
Li⁺ 1s²
The S orbital can hold a maximum number of just two electrons.
Helium atom has two electrons with electronic configuration of 1s²
Therefore Li⁺ = 1s² = He
Are you gonna list the ppl?