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Katen [24]
2 years ago
7

Addition of water to an alkyne gives a keto‑enol tautomer product. Draw an enol that is in equilibrium with the given ketone

Chemistry
1 answer:
Marrrta [24]2 years ago
7 0

Addition of water to an alkyne gives a keto‑enol tautomer product and that is the product changed into 2-pentanone, then the alkyne need to had been 1-pentyne. 2-pentyne might have given a combination of 2- and 3-pentanone.

<h3>What is the keto-enol means in tautomer?</h3>

They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.

  1. The enol that could provide 2-pentanone might had been pent-1- en - 2 -ol. Because an equilibrium favors the ketone so greatly, equilibrium isn't an excellent description.
  2. If the ketone have been handled with bromine, little response might be visible because the enol content material might be too low.
  3. If a catalyst have been delivered, NaOH for example, then formation of the enolate of pent-1-en - 2 - ol might shape and react with bromine.
  4. This might finally provide a bromoform product. Under acidic conditions, the enol might desire formation of the greater substituted enol constant with alkene stability.

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Help! What did I do wrong??
iogann1982 [59]

The molecules  of hydrogen gas that are  formed is  when 48.7 g  of sodium are added to water  is  6.375  x 10²³  molecules


  <u><em>calculation</em></u>

2 Na +2H₂O →  2 NaOH  +H₂

Step 1: find the moles  of sodium (Na)

moles =mass÷   molar mass

from periodic table the molar mass of Na = 23 g/mol

moles= 48.7 g÷ 23 g/mol =2.117 moles

Step 2:use the mole ratio to determine  the  moles of H₂

  from  given equation  Na:H₂ is 2:1

therefore the moles  of H₂ = 2.117 moles x 1/2=1.059 moles

Step 3: find the molecules of H₂ using the Avogadro's law

According  to  Avogadro's  law  1 mole = 6.02 x 10²³ molecules

                                                      1.059 moles = ?  molecules

by cross multiplication

= [(1.059 moles x 6.02 x10²³  molecules) /  1 mole] =6.375  x 10²³  molecules

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3 years ago
Read 2 more answers
Identify the precipitate that forms (if any) when aqueous solutions of barium nitrate and sodium sulfate are mixed.
Alborosie

The precipitate that forms when aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate.

Barium Nitrate is a colorless to white, odorless, crystalline powder. It is used in making fireworks, for green lights and neon lights, and in ceramic glazes.

Sodium Sulfate Anhydrous is the anhydrous, sodium salt form of sulfuric acid. Sodium ion is the principal cation of the extracellular fluid and plays a large part in the therapy of fluid and electrolyte disturbances.

When aqueous solutions of barium nitrate and sodium sulfate are mixed is barium sulphate, one soluble salt, sodium nitrate, and an insoluble salt, barium sulphate.

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4 0
1 year ago
During heat transfer, thermal energy always moves in the same direction: A. COLDHOT B. HOT COLD C. No movement D. HOTHOT
drek231 [11]

Answer: Option (B) is the correct answer.

Explanation:

Thermal energy is defined as the energy present within the molecules of a substance.

Also, when two objects that have different temperature and they are in contact with each other then heat will always flow from hot object to cold object.

For example, if a metal spoon is placed in a hot cup of coffee then heat will flow from hot coffee to the metal spoon.

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6 0
3 years ago
What is the mass number of an atom containing 35 protons and 45 neutrons?
vodka [1.7K]

Answer:

Explanation:

1. Weight = 35 P and 45 N = 80

2. Atom:  35P = 35 electrons

3. Bromine

4. It's a non metal. It's in column 17. It will gain 1 electron (normally).

5. Ion: 35 protons, 36 electrons

6. Charge: - 1 usually, but there are exceptions

7. Anions go to the Anode. The anode attracts minus charged elements.

8. In an uncharged state, element 36 would be next. That would be  Krypton which is always uncharged. It is a noble gas.

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