A sample of gas has a volume of 400 liters when its temperature is 20.C and its pressure
1 answer:
Answer:
V₂ = 145.35 L
Explanation:
Given data:
Initial volume = 400 L
Initial pressure = 300 mmHg (300/760 =0.39 atm)
Initial temperature = 20 °C (20 +273 = 293 K)
Final temperature = 273 K
Final volume = ?
Final pressure = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂ /T₁ P₂
V₂ = 0.39 atm × 400 L × 273 K / 293 K × 1 atm
V₂ = 42588 atm.L.K /293 K.atm
V₂ = 145.35 L
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