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uranmaximum [27]
3 years ago
15

If an atom has 17 protons and 18 neutrons, what is the charge of the atom's nucleus?​

Chemistry
1 answer:
seraphim [82]3 years ago
6 0

dont need time cause time waiting on nobody

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Which is colder dry ice or dioxide gas
Juli2301 [7.4K]
Dioxide gas because ita cooler
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Read 2 more answers
If 0.400 moles CO and 0.400 moles O2 completely react how many grams of CO2 are produces?
True [87]

If 0.400 moles CO and 0.400 moles O2 completely react, 17.604 grams of CO2 would be produced.

First, let us look at the balanced equation of reaction:

2CO + O_2 ---> 2CO_2

According to the equation, the mole ratio of CO and O2 is 2:1. But in reality, the mole ratio supplied is 1:1. Thus, CO is the limiting reactant while O2 is in excess.

Also from the equation, the ratio of CO consumed to that of CO2 produced is 1:1. Thus, 0.400 moles of CO2 would also be produced from 0.400 moles of CO.

Recall that: mole = mass/molar mass

Therefore, the mass in grams of CO2 that would be produced from 0.400 moles can be calculated as:

    Mass = mole x molar mass

                 = 0.400 x 44.01

                       = 17.604 grams

More on calculating mass from number of moles can be found here: brainly.com/question/12513822

7 0
3 years ago
The periodic table of elements is organized by the number of
skelet666 [1.2K]

Answer:

the increasing mass number

5 0
3 years ago
Which of the following is the correct formula for sulfuric acld?
Alona [7]

Explanation:

The answer is H2SO4 for sulphuric acid

6 0
3 years ago
If the specific heat of a solution is 4.18 J/goC, and you have 296 mL (1.03 g/mL) which increases in temperature by 6.9 degrees,
Sergeu [11.5K]

Answer:

Q = 8.8 kJ

Explanation:

Step 1: Data given

The specific heat of a solution = 4.18 J/g°C

Volume = 296 mL

Density = 1.03 g/mL

The temperature increases with 6.9 °C

Step 2: Calculate the mass of the solution

mass = density * volume

mass = 1.03 g/mL * 296 mL

mass = 304.88 grams

Step 3: Calculate the heat

Q = m*c*ΔT

⇒ with Q = the heat in Joules = TO BE DETERMINED

⇒ with m = the mass of the solution = 304.88 grams

⇒ with c = the specific heat of the solution = 4.18 J/g°C

⇒ with ΔT = the change in temperature = 6.9 °C

Q = 304.88 g * 4.18 J/g°c * 6.9 °C

Q = 8793.3 J = 8.8 kJ

Q = 8.8 kJ

8 0
3 years ago
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