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Ksivusya [100]
3 years ago
9

Suppose a bus arrives at a bus stop every 30 minutes. If you arrive at the bus stop at a random time what is the probability tha

t you will have to wait at least 5 min for the bus? A. 1/6
B.1/5
C.2/3
D.5/6
Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

Option A is correct.

Step-by-step explanation:

We are given with Total waiting time of a bus = 30 minutes

also given that we arrive at bus stand and have to wait for 5 minutes.

Probability=\frac{Number\:of\:favorable\:outcome}{Number\:of\:Total\:Outcome}

So, Probability=\frac{5}{30}=\frac{1}{5}

Therefore, Option A is correct

yarga [219]3 years ago
4 0

Answer:

D. 5/6

I just took it, it's correct.

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Two students walk in the same direction along a straight path, at a constant speed - one at .90 m/s and the other at 1.90 m/s.a.
anyanavicka [17]

Answer:

a)The second student arrive 7 minutes and 36 seconds sooner

b)They have to walk 598,51 m

Step-by-step explanation:

Speed= Distance/Time

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Difference=866,66-410,52= 456,14 seconds

In minutes

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Time¹= Time² + 5.50 min

5.50 min =350 seconds

Time²  =Speed¹ x Time¹ /Speed²

Time²  =Speed¹ x (Time² + 350 seconds  ) /Speed²

Time²  =0.9 x (Time² + 350 seconds  ) /1.9

Time²  =0,4737 x (Time² + 350 seconds  )

Time²  =0,4737 Time² + 165,79 seconds

Time²  - 0,4737 Time² = 165,79 seconds

0,5263 Time² = 165,79 seconds

Time² = 165,79 seconds/0,5263 =315,01 seconds

Distance=1,9 x 315,01 seconds = 598,51 m

5 0
3 years ago
Is a three-digt whole number
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