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Gnesinka [82]
3 years ago
15

Which best describes how an iconic bond forms

Biology
2 answers:
Minchanka [31]3 years ago
8 0

Answer:

Explanation:

It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion.

9966 [12]3 years ago
7 0

When an atom transfers/ gains a valence electron, it gains either a positive or negative charge. in the Proces, becoming an ion. because of the negative/positive charge the two ions are now attracted to each other.

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which of the following levels of protein organization shows the complete 3D arrangement of the polypeptide chain
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Proteins are the macromolecules made of hundreds of amino acids. Proteins are most varied class of biological molecules and show the greatest variety of structures. Many have detailed three-dimensional folding patterns that result in a compact form, but others do not fold up at all and they are in random conformations. The function of proteins depends on their structure.

The secondary structure of protein fold together to form the 3D arrangement of a polypeptide chain that results into Tertiary structure which is a functional protein.    


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Transpiration is the process of water movement through a plant and its evaporation from plant parts, such as the leaves, stems a
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Plants absorb water in a large amount because water is the only medium which is present in a plant for the transportation of minerals. So, the plant absorbs a lot of water even if it is lose by transpiration.

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2 years ago
Which of the following correctly describes a plant structure that contributes to a function SPECIFIC to plant cells? a. nucleus:
sergeinik [125]
I believe it’s B? I just dug out my old cell theory stuff lol that’s what Im gathering from it
6 0
3 years ago
24 Observe the illustration of the protein synthesis process above. What statement
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Answer:

j /

Explanation:

4 0
3 years ago
Most black bears (Ursus americanus) are black or brown in color. However, occasional white bears of this species appear in some
Sphinxa [80]

Answer and Explanation:

<em><u>The number of observed individuals</u></em>:

  • AA 42
  • AG 24
  • GG 21

<u><em>Total number of individuals, N</em></u>= 87 = 42 + 24 + 21

<u><em>Allelic frequencies</em></u>:

  • f(p) = (2 x AA + AG)/ 2 x N

       f (p)= (2 x 42 + 24) /2 x 87

       f (p) = (84 + 24) / 174

       f (p)= 108 / 174

      f (p) = 0.62

  • f (q) = (2 x GG + AG)/2 x N

        f (q) = (2 x 21 + 24 )/2 x 87

        f (q) = (42 + 24)/ 174

        f (q) = 66/174

        f (q) = 0.38

p + q = 1

0.62 + 0.38 = 1

<em><u>The expected genotypic frequency:</u></em>

  • F (AA)= 0.62 ² = 0.3844
  • F (AG) = 2 x A x G = 2 x 0.62 x 0.38 = 0.4712
  • F (GG) = 0.38 ² = 0.1444

AA + AG + GG = 0.3844 + 0.4712 + 0.1444 = 1

<u><em>The number of expected individuals</em></u>:

AA= (0.62)² x 87 = 0.3844 x 87 = 33.44

AG= (0.4712) x 87 = 40.99

GG= (0.38)² x 87 = 12.563

<u><em>Total number of expected individuals</em></u> = 33.44 + 40.99 + 12.563 = 87

<u><em>Chi square</em></u>= sum (O-E)²/E

  • AA= (O-E)² /E

        AA=(42 - 33.44) ² / 33.44

        AA= 2.2

  • AB= (O-E)² /E      

        AB= (24 - 40.99)²/ 40.99

        AB=7.04

  • BB=(O-E)² /E

        BB= (21-12.563)²/12.563

        BB= 5.66

<u><em>Chi square</em></u>= sum ((O-E)²/E) = 2.2 + 7.04 + 5.66 = 14.9

<u><em>Degrees of freedom</em></u> = genotypes - alleles = 3 - 1 = 2

p value less than 0.05

There is enough evidence to reject the nule hypothesis. The genotype frequencies are not in equilibrium.

5 0
3 years ago
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