All categories

3 years ago

Can someone just explain pre-image and image to me?

2 answers:

8 0

Answer: in doing transformations, the pre-image is the image you start with. The task is to move the pre-image so that it is contiguous with the (target) image. This is typically done by translation, rotation or reflection or a combination of those moves.

Hope that helps

Step-by-step explanation:

ollegr [7]3 years ago

3 0

Image is a related term of preimage. Preimage is a derived term of image.

In context terms the difference between preimage and image is that preimage is the set containing exactly every member of the domain of a function such that the member is mapped by the function onto an element of a given subset of the codomain of the function formally, of a subset b'' of the codomain ''y'' under a function ƒ, the subset of the domain ''x defined by while image is the subset of a codomain comprising those elements that are images of something.

As nouns the difference between preimage and image is that preimage is the set containing exactly every member of the domain of a function such that the member is mapped by the function onto an element of a given subset of the codomain of the function formally, of a subset b'' of the codomain ''y'' under a function ƒ, the subset of the domain ''x defined by while image is an optical or other representation of a real object; a graphic; a picture.

You might be interested in

Write in full text, no files plz.

slava [35]

Answer:

108 student tickets, and 176 adult tickets were sold.

I hope I helped, and thanks for the points!

Step-by-step explanation:

7 0

2 years ago

A video company randomly selected 100 of its subscribers and asked them how many hours of shows they watch per week. Of those su

Alik [6]

Answer:

1,135 people

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

Step-by-step explanation:

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

8 0

3 years ago

Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step

Lilit [14]

Answer: First option.

Step-by-step explanation:

The complete exercise is attached.

In order to solve this exercise, it is necessary to remember the following property:

The Multiplication property of Equality states that:

$If\ a=b\ then\ a*c=b*c$

In this case, the equation that Jada had is the folllowing:

$-\frac{4}{9}=\frac{x}{108}$

Jada needed to solve for the variable "x" in order to find its value.

The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:

$(108)(-\frac{4}{9})=(\frac{x}{108})(108)\\\\-48=x$

As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by $-\frac{4}{9}$ and the right side by $-\frac{9}{4}$ .

Therefore,you can conclude that Jada should have multiplied both sides of the equation by 108.

3 0

2 years ago

Read 2 more answers

In a set of 25 aluminum castings, four castings are defective (D), and the remaining twenty-one are good (G). A quality control

lianna [129]

Answer:

The sample space for selecting the group to test contains 2,300 elementary events.

Step-by-step explanation:

There are a total of N = 25 aluminum castings.

Of these 25 aluminum castings, n₁ = 4 castings are defective (D) and n₂ = 21 are good (G).

It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!(n-k)!}$

Compute the number of samples that are possible as follows:

${25\choose 3}=\frac{25!}{3!\times (25-3)!}$

$=\frac{25\times 24\times 23\times 22!}{3!\times 22!}\\\\=\frac{25\times 24\times 23}{3\times 2\times 1}\\\\=2300$

The sample space for selecting the group to test contains 2,300 elementary events.

6 0

3 years ago

In the diagram below of regular pentagon ABCDE, EB is drawn. What is the measure of AEB?

Drupady [299]

Answer:

36°

Step-by-step explanation:

< EAB = 180 - (360/5) = 180-72=108°

so, < AEB = (180-108)/2 = 72/2 = 36°

6 0

2 years ago

Can someone just explain pre-image and image to me? ​

Can someone just explain pre-image and image to me?