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Sonja [21]
3 years ago
5

A particle with a mass of 9.00 ✕ 10-20 kg is vibrating with simple harmonic motion with a period of 3.00 ✕ 10-5 s and a maximum

speed of 7.00 ✕ 103 m/s. (a) Calculate the angular frequency of the particle. rad/s (b) Calculate the maximum displacement of the particle.
Physics
1 answer:
Goshia [24]3 years ago
5 0

Answer:

(a) \omega=2.09*10^{5}\frac{rad}{s}

(b) A_{max}=0.033m

Explanation:

(a) The angular frequency is defined as:

\omega=2\pi f

Here f is the frequency of the particle, which is inversely proportional to its period:

f=\frac{1}{T}

Replacing, we have:

\omega=\frac{2\pi}{T}\\\omega=\frac{2\pi}{3*10^{-5}s}\\\omega=2.09*10^{5}\frac{rad}{s}

(b) The maximum displacement is given by:

A_{max}=\frac{v_{max}}{\omega}\\A_{max}=\frac{7*10^3\frac{m}{s}}{2.09*10^5\frac{rad}{s}}\\A_{max}=0.033m

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