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Hunter-Best [27]
3 years ago
15

A Cambra pouce car traveling at 28 m/s slow

Physics
1 answer:
natka813 [3]3 years ago
7 0

Answer:

t = 7.8 seconds

Explanation:

Given that,

The initial speed of the car, u = 28 m/s

Acceleration of the car, a = 3.6 m/s²

We need to find the time taken for the police car to come to Stop. When it stops, its final speed is equal to 0. So, using the equation of kinematics to find it i.e.

v=u+at\\\\0=28+3.6t\\\\t=\dfrac{28}{3.6}\\\\t=7.8\ s

So, the required time is 7.8 seconds.

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In a global convection cell less –dense air at the equator rises and flows towards the poles. And from pole, the dense air sinks down and flows back towards the equator.... This movement of air is also supported by the Earth's rotation known as Coriolis Effect.

4 0
3 years ago
Which group of measurements is the most precise? A) 2 g, 3 g, 4 g B) 2 g, 2.5 g, 3 g C) 2.0 g, 3.0 g, 4.0 g, 5.0 g D) 2.0 g, 3.0
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The answer to your question is A
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What is the value of acceleration as a body moves with an uniform speed
Levart [38]

Answer:

the value of acceleration as a body moves with an uniform speed is zero

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3 years ago
Explain how machines can be useful if the output is always less than the input work
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Because: Some of the work done by the machine is used to overcome the friction created by the use of the machine. ... Work output can never be greater than work input. Machines allow force to be applied over a greater distance, which means that less force will be needed for the same amount of work.

6 0
3 years ago
The​ half-life of a certain radioactive substance is 12 hours. There are 19 grams present initially. a. Express the amount of su
neonofarm [45]

Answer:

(a) N=19\times e^{-\lambda t}

(b) 15 hours

Explanation:

half life, T = 12 hours

No = 19 g

(a) Let N be the amount remaining after time t.

Let λ be the decay constant.

\lambda =\frac {0.6931}{T}

The equation of radioactivity used here is given by

N=N_{o}e^{-\lambda t}

N=19\times e^{-\lambda t}

(b) N = 8 gram

Substitute the values in above equation

\lambda =\frac {0.6931}{12}

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So, 8=19\times e^{-0.577t}

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Take natural log on both the sides

- 0.0577 t = - 0.865

t = 15 hours

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3 years ago
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